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liraira [26]
3 years ago
14

Hello everyone I have a question for you today. So you know we have discovered black holes and have theorized about white holes

so let me ask you without you going to the internet and looking it up what would happen if a white hole and a black hole collided?
Physics
1 answer:
Scrat [10]3 years ago
8 0

Answer:

White hole is an impossible object in universe. ... This means that in a hypothetical universe where there is a black and a white hole, in a short time after their first interaction the white hole will become another black hole so that the system will end up with two black holes.

You might be interested in
So lost on this one number 1 ?
kirza4 [7]

Read each statement, one at a time, and form the picture in your mind.

<em>Statement #1</em> should make you feel all warm and fuzzy inside.

Statements #2, #3, and #4 should make your red flag wave on the inside, and should make you giggle on the outside when you realize how absurd each of those is.

5 0
3 years ago
If the plane is flying in a horizontal path at an altitude of 98.0 m above the ground and with a speed of 73.0 m/s, at what hori
snow_lady [41]

Explanation:

The given data is as follows.

     height (h) = 98.0 m,     speed (v) = 73.0 m/s,

Formula of height in vertical direction is as follows.

          h = \frac{gt^{2}}{2},

or,      t = \sqrt{\frac{2h}{g}}

Now, formula for the required distance (d) is as follows.

       d = vt

          = v \sqrt{\frac{2h}{g}}  

        = 73.0 m/s \sqrt{\frac{2 \times 98.0 m}{9.8 m/s^{2}}}  

          = 326.5 m

Thus, we can conclude that 326.5 m is the horizontal distance from the target from where should the pilot release the canister.

8 0
3 years ago
A wire of radius 5 x 10⁻⁴ m is needed to prepare a coil of resistance 40 Ω. The resistivity of the material of the wire is 3.14x
SIZIF [17.4K]

Answer:

100 m

Explanation:

From the question,

R = Lρ/A.................... Equation 1

Where R = resistance of the wire, L = length of the wire, ρ = resistivity of the wire, A = cross sectional area of the wire.

But,

A = πr².................... Equation 2

Where r = radius of the wire.

Substitute equation 2 into equation 1

R = Lρ/πr²

Make L the subject of the equation

L = Rπr²/ρ...................... Equation 3

Given: R = 40 Ω, r = 5×10⁻⁴ m, ρ = 3.14×10⁻⁷ Ωm

Constant: π = 3.14

Substitute these values into equation 3

L = [40×3.14×( 5×10⁻⁴)²]/ (3.14×10⁻⁷)

L = 40×3.14×25×10⁻⁸/(3.14×10⁻⁷)

L = 100 m

Hence the length of the wire is 100 m

4 0
2 years ago
A biker pedals hard to ride his bike to the top of a 44 m hill. He decides to let his bike coast down the hill, and is having so
Dafna11 [192]

Answer:

The bikers speed at the top of other hill is <u>25.82 m/s.</u>

Explanation:

Considering the biker is riding on a frictionless surface.

∴ There is no non-conservative or external force acting on the biker.

Hence we can conserve the energy of biker and bike as a system.

Let,

h_{1} = 44m

h_{2} = 10m

Since the biker starts from rest , his initial speed v_{1} = 0 m/s

Let final speed of the bike at the top of other hill be v_{2}.

∴ Initial Energy (at the top of 44m hill) = mgh_{1}

  Final Energy  (at the top of 10m hill) =  mgh_{2} + \frac{1}{2}mv_{2} ^{2}.

Conserving both the energies , we get

mgh_{1} = mgh_{2} + \frac{1}{2}mv_{2} ^{2}

∴ v_{2} = \sqrt{2g(h_{1}-h_{2} )}

Substituting the values for g , h_{1} , h_{2} , we get

v_{2} = 25.82 m/s

6 0
3 years ago
Select the correct answer.
LekaFEV [45]
D is not a scientific experiment.
4 0
3 years ago
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