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puteri [66]
3 years ago
6

What connection may be drawn between the graphs of sin and cos and the signs of both functions relating to the 4 quadrants?

Mathematics
1 answer:
lisov135 [29]3 years ago
7 0

Sin is negative where as cos is positive in the 4th quadrant.

Step-by-step explanation:

Sin, cos and tan are all positive in the 1st quadrant. Sin is only positive in the 2nd quadrant. Tan is only positive in the 3rd quadrant.Cos is only positive in the 4th quadrant.

Learn More

Graphs of sin and cos : brainly.com/question/9554579

Keywords: graphs, sin, cos, quadrant

#LearnwithBrainly

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Richard buys one tooth cleaning kit for $25 and a toothbrush for $15. He spends the rest of his money on body soap. He has $80 a
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13.   There are 45 employees who each put in 97 hours on a project. What are the total number of hours worked on the project?
Tcecarenko [31]
You would do 45 x 97 which equals 4365
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3 years ago
In an experiment, college students were given either four quarters or a $1 bill and they could either keep the money or spend it
gavmur [86]

Answer:

a) P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341

b) P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659

c)  A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

Step-by-step explanation:

Assuming the following table:

                                                     Purchased Gum      Kept the Money   Total

Students Given 4 Quarters              25                              14                      39

Students Given $1 Bill                       15                               29                    44

Total                                                   40                              43                     83

a. find the probability of randomly selecting a student who spent the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student spent the money"

For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{40}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{15}{83}

And if we replace we got:

P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341

b. find the probability of randomly selecting a student who kept the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student kept the money"

For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{43}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{29}{83}

And if we replace we got:

P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659

c. what do the preceding results suggest?

For this case the best solution is:

A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

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B. 90/360, because this is 1/4 from circle. It's even shown in the picture.
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