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Kay [80]
3 years ago
9

Suppose that $2000 is invested at a rate of 4%, compounded semiannually. Assuming that no withdrawals are made, find the total a

mount after 5 years. Do not round any intermediate computations, and round your answer to the nearest cent. ​
Mathematics
1 answer:
creativ13 [48]3 years ago
5 0

Answer:

Step-by-step explanation:

A = P(1+r/n)^ nt

A = 2000(1+.04/2)^(5*2)

A = 2000(1.02)^{10} = $2437.99

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Is the number of miles to the next service station and the number of kilometers linear
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A company needs $5,400,000 in 14 years in order to expand their factory. How much should the company invest each week if the inv
ludmilkaskok [199]

Answer: the company should invest $12191 each week

Step-by-step explanation:

The amount that the company needs is $5,400,000

We would apply the periodic interest rate formula which is expressed as

P = a/[{(1+r)^n]-1}/{r(1+r)^n}]

Where

P represents the weekly payments.

a represents the amount that the company needs

r represents the rate.

n represents number of weekly payments. Therefore

a = 5,400000

There are 52 weeks in a year

r = 0.079/52 = 0.0015

n = 52 × 14 = 728

Therefore,

P = 5400000/[{(1+0.0015)^728]-1}/{0.0015(1+0.0015)^728}]

5400000/[{(1.0015)^728]-1}/{0.0015(1.0015)^728}]

P = 5400000/{2.98 -1}/[0.0015(2.98)]

P = 5400000/(1.98/0.00447)

P = 5400000/442.95

P = $12191

3 0
3 years ago
Help please!
kupik [55]

Answer:

that is a whole lot of simple intrest

7 0
3 years ago
Solve for q.<br><br> s = 4p + 4q solve the equation
Harlamova29_29 [7]

Answer:

q = \frac{s -4p}{4}\\

Step-by-step explanation:

s = 4p +4q \\ 4p +4q = s \\ 4p +4q -4p = s -4p \\ 4q = s - 4p \\ \frac{4q}{4} = \frac{s -4p}{4} \\ q = \frac{s -4p}{4}

4 0
3 years ago
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