Answer:
12 : 3 : 1
white : yellow : green
Explanation:
Given that genes A and B control the fruit colour in following ways:
A_B_ or A_bb = white
aaB_ = yellow
aabb = green
The genes undergo independent assortment so:
AaBb X AaBb =
A_B_ : A_bb : aaB_ : aabb
9 : 3 : 3 : 1
white : white : yellow: green
12 : 3 : 1
Hence, ratio of white : yellow : green is 12: 3: 1
B
Explanation
Sodium Fluoride
Answer:
The probability that the child will have type blood B equals <u>3/16</u>.
Explanation:
<u>Available data:</u>
- Individuals with the rare Bombay blood phenotype lack both the A and B antigens in individuals and/or are of hh genotype.
- Cross between two parents that are both of I A I B Hh genotype
Cross: IAIB Hh x IAIB Hh
Gametes) IAH, IAh, IBH, IBh
IAH, IAh, IBH, IBh
Punnett square) IAH IAh IBH IBh
IAH IAIAHH IAIAHh IAIBHH IAIBHh
IAh IAIAHh IAIAhh IAIBHh IAIBhh
IBH IAIBHH IAIBHh IBIBHH IBIBHh
IBh IAIBHh IAIBhh IBIBHh IBIBhh
F1) Genotype
- 1/16 IAIA HH
- 2/16 IAIAHh
- 1/16 IAIAhh
- 2/16 IAIBHH
- 4/16 IAIBHh
- 2/16 IAIBhh
- 1/16 IBIBHH
- 2/16 IBIBHh
- 1/16 IBIBhh
Phenotype
- 3/16 Blood type A
- 6/16 Blood type AB
- 3/16 Blood type B
- 3/16 Blood type 0
Water and wind it the answer
I would think most likely red and white