Answer:
i) The time taken for 1500 records = 15 seconds.
ii) The time taken for 1500 records = 50 seconds.
Explanation:
A is an O(n) algorithm.
An algorithm with O(n) efficiency is described as a linearly increasing algorithm, this mean that the rate at which the input increases is linear to the time needed to compute that algorithm with n inputs.
From the question, it is given that for 1000 records, the time required is: 10 seconds.
Algorithm time taken is O(n)
Hence,
1) For 1,500 records
=> 10/1000 = x/1500
=> 10x1500/1000 = x
x = 15 seconds
Thus, the time taken for 1500 records = 15 seconds.
2) For 5,000 records
=> 10/1000 = x/5000
=> 10x5000/1000 = x
x = 50 seconds
Thus, the time taken for 1500 records = 50 seconds.
int main() {
string simon_Pattern;
string user_Pattern;
int userScore;
int i;
user_Score = 0;
simon_Pattern = "RRGBRYYBGY";
user_Pattern = "RRGBBRYBGY";
for (i = 0; i <= simson_pattern.length; i++) {
if (simon_Pattern[i] == user_Pattern[i]) {
user_Score = user_Score + 1;
} else {
break;
}
}
cout << "userScore: " << user_Score << endl;
return 0;
}
Here it uses two string variable to store “simson’s pattern and user’s pattern”. Then a “for loop” is executed till the end of the string. Inside the for loop both the strings are compared character by character and when found the score is added. If not for loop is exited and finally the score is displayed.
The Correct choice is " True "
When the animation and the graphic designs are used to sell products or services, it is known as multimedia advertising.
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If your choices are the following:
<span>A. Legend
B. Chart area
C. Slices
D. Chart elements
Then the answer is letter B. </span>Chart area is the boundary that contains all the chart and all its elements including the chart titles, legends, plot area, labels, etc.
