Answer:
a=input("Amount in pennies")
b=int(a)
dollars=0
dimes= 0
quarters=0
nickels=0
pennies = 0
dollars = int(b/100)
b= b- dollars *100
quarters=int(b/25)
b=b-quarters*25
dimes = int(b/10)
b = b -dimes*10
nickels=int(b/5)
b=b - nickels * 5
pennies = b
print(dollars)
print(dimes)
print(nickels)
print(pennies)
Explanation:
The required program is in answer section. Note, the amount is entered in pennies.
Answer:
-
= 1
= 1
Explanation:
Argon atom has atomic number 18. Then, it has 18 protons and 18 electrons.
To determine the quantum numbers you must do the electron configuration.
Aufbau's principle is a mnemonic rule to remember the rank of the orbitals in increasing order of energy.
The rank of energy is:
1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s < 4f < 5d < 6p < 7s < 5f < 6d < 7d
You must fill the orbitals in order until you have 18 electrons:
- 1s² 2s² 2p⁶ 3s² 3p⁶ : 2 + 2 + 6 + 2 + 6 = 18 electrons.
The last electron is in the 3p orbital.
The quantum numbers associated with the 3p orbitals are:
- = 1 (orbitals s correspond to = 0, orbitals p correspond to = 1, orbitals d, correspond to = 2 , and orbitals f correspond to = 3)
- can be -1, 0, or 1 (from - to + )
- the fourth quantum number, the spin can be +1/2 or -1/2
Thus, the six possibilities for the last six electrons are:
- (3, 1, -1 +1/2)
- (3, 1, -1, -1/2)
- (3, 1, 0, +1/2)
- (3, 1, 0, -1/2)
- (3, 1, 1, +1/2)
- (3, 1, 1, -1/2)
Hence, the correct choice is:
- = 1
- = 1
Answer:
<u>First test:</u> Give a list of disordered numbers to the sorting algorithm an examine if the output is correctly sorted.
<u>Second test:</u> Give a list of ordered numbers to the sorting algorithm an analyze if the output is still correctly ordered.
<u>Third test:</u> Give a list of ordered numbers and some non-numeric values to the sorting algorithm and check how is managed the exception in case of error or if the output is correctly ordered.
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<span>A few short tips for writing cover letters. i dont know if thats the answer you looking for</span>
