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nata0808 [166]
3 years ago
9

Find the difference:7 7/8-3 1/4=?

Mathematics
1 answer:
Arlecino [84]3 years ago
8 0

Answer:

4 5/8

Step-by-step explanation:

7 7/8 - 3 1/4

7 7/8 - 3 2/8

4 5/8

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ASAP! GIVING BRAINLIEST! Please read the question THEN answer CORRECTLY! NO guessing. Show your work OR give an explaination.
erma4kov [3.2K]

Answer:

y =  x² - 8x + 17

Step-by-step explanation:

Recall this formula:

y = a(x-h)² + k

Original equation was y = x², which in this form looks like

y = 1(x - 0)² + 0

If the shape of the graph didn't change, that means that a (the compressor/intensifier) stayed the same (a - value) meaning we can write the equation as..

y = (x-h)² + k

Remember, (h, k) is the vertex, which looking from your graph is at (4, 1)

y = (x - 4)² + 1

y = x^2- 8x + 16+1

y = x² - 8x + 17

8 0
3 years ago
Burger patties come packed 8 in a package, and burger buns come packed 12 in a package. We want to buy the least number of patti
seraphim [82]

Answer: but will soon find out

Step-by-step explanation:

6 0
2 years ago
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WILL GIVE BRAINLIEST!
hammer [34]

Answer:

The three consecutive odd integers are: -1, 1, 3

Step-by-step explanation:

The three consecutive odd integers be x, x + 2, x + 4

Now according to the question

It is mentioned that

The four times the middle integer is two lower than tfhe sum of the first and third

i.e.

4(x+2) = [x + (x+4)] + 2

4x + 8 = 2x + 6

2x = -2

x = -1

Hence, The three consecutive odd integers are: -1, 1, 3

8 0
2 years ago
Find the solution to the equation. URGENT
timurjin [86]

Answer:

x + 6 + x + 6 + x + 6 + x + 6 + x + 6 x + 6 + x + 6 + x + 6 = 120

aka 8(6 + x) = 120

48 + 8x = 120

you want to get 8x on one side so you will subtract 48 on both sides - whatever you do to obe side you must do on the other side.

8x = 72

now you want the x by its self so to undo multiplication you need to divide, and divide on both sides.

x = 9

Solution: x = 9

5 0
2 years ago
Pls answer!!!!!!!!!!
Vinil7 [7]

Answer:

don't

know

Step-by-step explanation:

4 0
2 years ago
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