<h2> hope it helps.</h2><h2>stay safe healthy and happy.</h2>
Answer:
50%
Explanation:
Let's assume that the allele "T" gives the normal phenotype while the recessive allele "t" imparts the disease and is lethal in homozygous condition. The genotype of each of the two carrier parents would be "Tt". A cross between Tt and Tt would give the progeny in the following genotype ratio=
Tt x Tt= 1/4 TT: 1/2 Tt: 1/4 tt
Therefore, 1/2 or 50% progeny would be the carrier for the Tay-Sachs disease.
The sugar found in DNA contains one less oxygen molecule than the sugar found in RNA.
Hamsters are very small and could be harmful. Guinea pigs are very calm.