Bx must be the sum of the numbers in the bracket and c must be the product. So we need to choose 2 numbers that multiply to make 3 and add to make -4.
A negative x negative = positive so
-3*-1=3
-3-1=-4
Therefore:
(x-3)(x-1)
Answer:
8th term of geometric sequence is 312500
Step-by-step explanation:
Given :
and common ratio (r) = 5
We have to find the 8th term of the geometric sequence whose
and common ratio (r) = 5
Geometric sequence is a sequence of numbers in which next term is found by multiplying by a constant called the common ratio (r).
......(1)
where
is nth term and a is first term.
For given sequence
a can be find using
and r = 5
Substitute in (1) , we get,
Thus, 8th term of the sequence denoted as 
Substitute n= 8 in (1) , we get,

Thus 8th term of geometric sequence is 312500
2/7. There are 2 G's out of a total of 7 letters in the word.