Question

Rewrite the following radical expressions as equivalent exponential expressions. c.1/(3√16 )

Answer 1

Answer:

$\frac{1}{3\sqrt{16}}$ = $(16)^{\frac{-1}{2}}.3^{-1}$

Step-by-step explanation:

We have given the expression in radical form as  $\frac{1}{3\sqrt{16}}$

We have to convert this radical form in exponential form

We know that  $\frac{1}{3\sqrt{16}}$ can be written as $\frac{1}{3\sqrt{16}}=\frac{1}{3}\times \frac{1}{(16)^{\frac{1}{2}}}$

Now if we write $\frac{1}{3}$ in exponential form then we can write as $3^{-1}$ ( property of exponent )

And $\frac{1}{(16)^{\frac{1}{2}}}=(16)^{\frac{-1}{2}}$

So  $\frac{1}{3\sqrt{16}}$ = $(16)^{\frac{-1}{2}}.3^{-1}$