5. What skill is unique to reading online?

Write a public member function which replace that replaces one occurrence of a given item in the ArrayBag with another passed as

ira [324]

Answer:

The method is written in Java

public static boolean abc(int [] ArrayBag,int num, int replace){

Boolean done = false;

for(int i =0; i<ArrayBag.length;i++){

if(ArrayBag[i] == num){

ArrayBag[i] = replace;

done = true;

}

for(int i = 0;i<ArrayBag.length;i++){

System.out.println(ArrayBag[i]+" ");

}

return done;

}

Explanation:

The method is written in java

The arguments of the method are:

1. ArrayBag -> The array declares as integer

2. num -> The array element to check the presence

3. replace - > The replacement variable

This line defines the method as boolean.

public static boolean abc(int [] ArrayBag,int num, int replace){

This line declares a boolean variable as false

Boolean done = false;

The following iterates through the elements of the array

for(int i =0; i<ArrayBag.length;i++){

This checks if the array element exist

if(ArrayBag[i] == num){

If yes, the array element is replaced

ArrayBag[i] = replace;

The boolean variable is updated from false to true

done = true;

}

The following iteration prints the elements of the array

for(int i = 0;i<ArrayBag.length;i++){

System.out.println(ArrayBag[i]+" ");

}

This prints returns the boolean thats indicates if replacement was done or not.

return done;

}

Attached to this solution is the program source file that includes the main method of the program

Download txt

5 0

3 years ago

How can i change ip address

JulijaS [17]

I believe your answer would be:

1: Open the command prompt window. Do this by clicking the "Start" button, and then selecting "Run." In the window that appears, type "cmd" into the text box and click the "OK" button.

2: Release the computer's current IP address. To do this, type "ipconfig /release" into the command prompt window and press Enter.

3: Acquire a new IP address. Do this by typing "ipconfig /renew" into the command prompt window and pressing Enter. This should assign the computer a new IP address, which will be different from the previous address.

4: Cycle your modem's power. If the above steps don't work, you can try renewing your IP address by cycling your modem's power. Turn off both your computer and your modem (and your router, if you have one). Wait at least 5 minutes, then turn everything back on. If your computer is set to receive an IP address dynamically (the most likely configuration), you should be assigned a new IP address automatically.

5: Check to make sure your IP address has changed. To do this, you can log on to a number of different websites that tell you your IP address.

Hope I helped, if so may I get brainliest and a thanks?

Thank you, Have a good day! =)

7 0

4 years ago

8. Given the array String[] words, which already contains 1 or more values, write a block of code which counts and returns the n

Vikentia [17]

Answer:

Following are the code to this question:

public class Main//defining a class

{

public static void main(String[] arg)//defining main method

{

String[] words={"Key","day", "Know", "kind"};//defining array of String words

int x=0;//defining integer variable for count value

for(int i=0;i<words.length;i++)//defining for loop for count value

{

if(words[i].startsWith("k")||words[i].startsWith("K"))//use if block to check word start from k

x=x+1;//increment the value of x

}

System.out.print("The number of letters which starts from k is: "+ x);//print value with message

}

Output:

The number of letters which starts from k is: 3

Explanation:

In this code, inside the main method an array of String "words" is defined that hold a value, and in the next step an integer variable "x" is defined, which is used to count the letters, which starts from k.

For this, a for loop is used that counts the value and in this an, if block is defined that uses the "startsWith" method to check the value and increment the value of x and at the last, it prints its value.

7 0

3 years ago

[20 pts] Write the function rectangle(perimeter, area), which takes two positive integers, perimeter and area. It returns an int

MrRissso [65]

Hi, you haven't provided the programing language in which you need the code, I'll explain how to do it using Python, and you can follow the same logic to make a program in the programing language that you need.

Answer:

import math

def rectangle(perimeter, area):

l1_1 = (perimeter+math.sqrt((perimeter**2)-(16*area)))/4

l1_2 = (perimeter-math.sqrt((perimeter**2)-(16*area)))/4

l2_1 = area/l1_1

l2_2 = area/l1_2

print(l1_1,l2_1)

print(l1_2,l2_2)

if l1_1.is_integer() and l2_1.is_integer() and l1_1>0 and l2_1>0:

return(int(max(l1_1,l2_1)))

elif l1_2.is_integer() and l2_2.is_integer() and l1_2>0 and l2_2>0:

return(int(max(l1_2,l2_2)))

else:

return(None)

Explanation:

We import math to make basic operations
We define the rectangle function that receives perimeter and area
We calculate one of the sides (l1_1) of the rectangle using the quadratic equation to solve 2h^2 - ph + 2a = 0
We calculate the second root of the quadratic equation for the same side (l1_2)
We calculate the second side of the rectangle using the first root on w = a/h
We calculate the second side of the rectangle using the second root on w= a/h
We verify that each component of the first result (l1_1, l2_1) is an integer (using the build-in method .is_integer) and greater than 0, if True we return the maximum value between them (using the max function) as w
If the first pair of sides evaluate to False we check the second root of the equation and if they meet the specification we return the max value
if all the if statements evaluate to false we return None to indicate that not positive or integer sides were found

7 0

3 years ago

_____ are the younger edge of gen y who have never lived without the internet or easy access to cell phones.

Sophie [7]

Generation Y are the people age 14-37, which means they are born 1977 - 2000.Tweens are the younger edge of gen Y who have never lived without the internet or easy access to cell phones.

8 0

3 years ago