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White raven [17]
3 years ago
6

4a² + 8a -100 Factor

Mathematics
1 answer:
nlexa [21]3 years ago
8 0
This is not factorable. It can be easily tested using the radicand expression of the quadratic equation. (Perfect square= Factorable, No Perfect= Not Factorable.)
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At a school fair 70% of the people are under 16 years old. One third of the people remaining are teachers. If there are 21 teach
Tamiku [17]
In the fairest school 70% are below 16 years old 1/3 are teachers which is equals to = 21 Let’s start solving: => 1/3 of 100% => 100 / 3 = 33.33% thus 33.33% = 21 => 21 x 3 = 63, is the total number of people in the school. Let’s try solving the number of people below 16 years old Have you notice that you are asking for a 70% of students but there are already 33.33% of teacher. Thus your given problem is not right already. => 100% - 33.33% = 66.67% that’s the only remaining percentage and not 70% => 63 * .6667 = 42.0021 Thus, there are around 42 people who are 16 years old younger.
3 0
3 years ago
3
lara31 [8.8K]

Answer:

0

Step-by-step explanation:

Given the points J (1,-10) and K (7, 2)

From the section formula

(x,y)=\left(\dfrac{mx_2+nx_1}{m+n}, \dfrac{my_2+ny_1}{m+n}\right)

The y-coordinates of the point that divides the directed line segment from J to K into a ratio of 5:1 is obtained using the formula:

y=\dfrac{my_2+ny_1}{m+n}\\m=5, n=1, y_1=-10, y_2=2\\Therefore:\\y=\dfrac{5*2+1*-10}{5+1}\\=\dfrac{10-10}{6}\\=0

The y-coordinates of the point that divides the directed line segment from J to K into a ratio of 5:1 is 0.

5 0
3 years ago
Im confused, please helpp?
mafiozo [28]

The answer is D. THe last one.

8 0
2 years ago
Read 2 more answers
PLZ HELP! 20 POINTS!!
ivann1987 [24]
Given list of values
A = {23, 34, 19, 10, 9, 20, 40, 43, 28, 29, 36, 13, 27, 23, 36, 37, 7}

Sort list A to get list B
B = {7, 9, 10, 13, 19, 20, 23, 23, 27, 28, 29, 34, 36, 36, 37, 40, 43}

The smallest value is 7, so the min is 7
The largest value is 43, so the max is 43

Look through list B to find the middle-most value. What you can do is cross off each pair of outer values (see figure 1 in the attached images) until you are left with the middle value
Or you can note how there are 17 values so the median is at slot 9 (there are 8 values below the median; 8 values above the median; the 8 is from 17/2 = 8.5)

Once you know the median is 27, we split the list B into two parts
The first part, we'll call it L for lower half is
L = {7, 9, 10, 13, 19, 20, 23, 23}
which is the list of all values lower or smaller than the median.
The median of list L is 16 because its the midway point between 13 and 19. We can compute (13+19)/2 = 32/2 = 16. This is the value of Q1

The upper half U is
U = {28, 29, 34, 36, 36, 37, 40, 43}
this list shows all the values larger than the median.
The value of Q3 is 36. We find the midpoint of 36 and 36 which is just 36.
The value of Q3 is the same as the median of list U

------------------------------------------------

Five Number Summary:
Min = 7
Q1 = 16
Median = 27
Q3 = 36
Max = 43

This five number summary is then used to construct the box-and-whisker plot. See figure 2 in the attached images. The diagram shows how each piece of the boxplot is put together (eg: the left edge of the box is the value of Q1). 

5 0
2 years ago
Please help. If f(x)= 2^x-1+3 and g(x)=5x-9 what is (f-g)(x)??
Readme [11.4K]

( f + g ) (x) = –2x + 6

( f – g ) (x) = 8x – 2

( f  × g ) (x) = –15x2 + 2x + 8

<span>\mathbf{\color{purple}{ \left(\small{\dfrac{\mathit{f}}{\mathit{g}}}\right)(\mathit{x}) = \small{\dfrac{3\mathit{x} + 2}{4 - 5\mathit{x}}} }}<span><span>(<span><span>​g</span>​<span>​f</span><span>​​</span></span>)</span>(x)=<span><span>​<span>4−5x</span></span>​<span>​<span>3x+2</span></span><span>​​</span></span></span></span>

4 0
2 years ago
Read 2 more answers
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