Halp meh ples friends :D

Stacey wishes to make a hamburger which is lower in fat without having to give up the great taste. She purchases 5 pounds of gro

STALIN [3.7K]

Answer:

%P = 8%

the percentage of fat in the mixture is 8%

Step-by-step explanation:

Given;

The percentage of fat in the mixture is;

%P = total mass of fat in mixture/total mass of mixture × 100%

%P = F/T × 100% ….....1

Mass of fat in mixture is;

She purchases 5 pounds of ground beef which is 15% fat

F1 = 15% of 5 pounds = 0.15×5 pounds

F1 = 0.75 pound

and combines it with 7 pounds of ground turkey which is only 3% fat

F2 = 3% of 7 pounds = 0.03 × 7

F2 = 0.21 pound

Total mass F = F1 + F2

F = 0.75+0.21

F = 0.96 pound

Total mass of mixture T = 5 + 7 pounds

T = 12 pounds.

From equation 1,

%P = F/T × 100%

%P = 0.96/12 × 100%

%P = 0.08×100%

%P = 8%

the percentage of fat in the mixture is 8%

5 0

3 years ago

Which is the perimeter of the triangle below?<br>13/24 foot<br>22/24 foot<br>28/24 foot

tensa zangetsu [6.8K]

Answer:

c. 22/24

Step-by-step explanation:

perimeter = 3/8 + 3/8 + 1/6

perimeter = 22/24 or 11/12

3 0

3 years ago

4x - 7 (2 - x) = 3x + 2

juin [17]

Answer:

x=2

Step-by-step explanation:

4x−7(2−x)=3x+2

4x+(−7)(2)+(−7)(−x)=3x+2(Distribute)

4x+−14+7x=3x+2

(4x+7x)+(−14)=3x+2(Combine Like Terms)

11x+−14=3x+2

11x−14=3x+2

Step 2: Subtract 3x from both sides.

11x−14−3x=3x+2−3x

8x−14=2

Step 3: Add 14 to both sides.

8x−14+14=2+14

8x=16

Step 4: Divide both sides by 8.

x=2

3 0

3 years ago

An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t

USPshnik [31]

The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

$\displaystyle\int_a^bf(x)\,\mathrm dx$

Split up the interval $[a,b]$ into $n$ equal subintervals,

$[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]$

where $a=x_0$ and $b=x_n$ . Each subinterval has measure (width) $\dfrac{a-b}n$ .

Now denote the left- and right-endpoint approximations by $L$ and $R$ , respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are $\{x_0,x_1,\cdots,x_{n-1}\}$ . Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, $\{x_1,x_2,\cdots,x_n\}$ .

So, you have

$L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)$
$R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)$

Now let $T$ denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

$T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)$

Factoring out $\dfrac12$ and regrouping the terms, you have

$T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)$

which is equivalent to

$T=\dfrac12\left(L+R)$

and is the average of $L$ and $R$ .

So the trapezoidal approximation for your problem should be $\dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2$

4 0

3 years ago

NEED HELP PLZ HELP ME ….

Katyanochek1 [597]

Answer:

R= -0.95

Step-by-step explanation:

HOPE THIS HELPS :)

7 0

2 years ago

Halp meh ples friends :D​

Halp meh ples friends :D