Answer:
each student must make 5 posters in one hour
Step-by-step explanation:
The equitable thing is that each student makes an equal number of posters at the established time, knowing that there must be 60 posters and there are 12 students, these numbers must be divided so we will have the same amount for each student:
60/12 = 5
Which means that each student must make 5 posters in one hour so that everything turns out well
2. Because it is being reflected across the X axis, the X coordinate would change signs, but the Y coordinate would remain the same sign.
A(-6,-4) would become A'(6,-4)
B(-3,5) would become B'(3,5)
C(1,-1) would become C'(-1,-1)
The answer would be the third choice.
3. Reflected across the Y axis, the X would stay the same sign and the Y would change signs.
P(-2,-4) would become P'(-2,4)
Q(2,-5) would become Q'(2,5)
R(-1,-8) would become R'(-1,8)
The answer would be the second choice.
The rest of the statement is (3x+1) = 3x²+22x+7.
The divisor is one factor, and the quotient is the second factor. The factors get multiplied to make the dividend.
Answer:
<u>The expression to describe this sequence is Aₙ = (n - 1) * 1 - 6</u>
Step-by-step explanation:
1. Let's write an expression to describe the sequence which first four terms are as follows:
- 6, -5, -4, - 3.....
Aₙ = (n - 1) * 1 - 6; A₁ = - 6
A₁ = (n - 1) * 1 - 6 = (1 - 1) * 1 - 6 = 0 * 1 - 6 ⇒A₁ = - 6
A₂ = (n - 1) * 1 - 6 = (2 - 1) * 1 - 6 = 1 * 1 - 6⇒ A₁ = - 5
A₃ = (n - 1) * 1 - 6 = (3 - 1) * 1 - 6 = 2 * 1 - 6⇒ A₁ = - 4
A₄ = (n - 1) * 1 - 6 = (4 - 1) * 1 - 6 = 3 * 1 - 6⇒ A₁ = - 3
A₅ = (n - 1) * 1 - 6 = (5 - 1) * 1 - 6 = 4 * 1 - 6⇒ A₁ = - 2
A₆ = (n - 1) * 1 - 6 = (6 - 1) * 1 - 6 = 5 * 1 - 6⇒ A₁ = - 1
A₇ = (n - 1) * 1 - 6 = (7 - 1) * 1 - 6 = 6 * 1 - 6⇒ A₁ = 0
I would but I’m like really bad at math so
