Currently, astronomers are observing the universe across many different regions of the electromagnetic spectrum, from gamma rays
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Answer:
E = 1.19 N/C
Explanation:
Let's first determine the length of the arc which can be given as:
L= Rθ
where:
L = length of the arc
R = radius of curvature
θ = angle in radius
L = (9.09×10⁻²m)(2.59)
L = (0.0909)(2.59)
L = 0.235431 m
Then, the magnitude of electric field that Q produces at the center of curvature can be calculated by using the formula:
Since
where;
L = length
Q = charge
λ = density of the charge;
then substituting for λ, we have :
substituting our given parameter; we have:
E = 1.1889 N/C
E = 1.19 N/C
∴ the magnitude of the electric field that Q produces at the center of curvature = 1.19 N/C
Answer:
The box is moved at constant speed, then the change in kinetic energy is zero.
Explanation:
Let suppose that box moves at constant speed, meaning that its kinetic energy (), measured in joules, is expressed by the following equation:
(1)
Where:
- Mass, measured in kilograms.
- Speed, measured in meters per second.
If the box moves at constant speed, then we notice that , therefore,
. In a nutshell, if the box is moved at constant speed, then the change in kinetic energy is zero.