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inna [77]
3 years ago
6

Is the box moving at a constant speed? Explain how you know. What does this tell you about the kinetic energy of the system

Physics
1 answer:
mars1129 [50]3 years ago
8 0

Answer:

The box is moved at constant speed, then the change in kinetic energy is zero.

Explanation:

Let suppose that box moves at constant speed, meaning that its kinetic energy (K), measured in joules, is expressed by the following equation:

K = \frac{1}{2}\cdot m\cdot v^{2} (1)

Where:

m - Mass, measured in kilograms.

v - Speed, measured in meters per second.

If the box moves at constant speed, then we notice that v_{f}^{2}-v_{o}^{2} = 0, therefore, \Delta K = 0. In a nutshell, if the box is moved at constant speed, then the change in kinetic energy is zero.

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If a closed series circuit has a voltage of 12 V and R1 = 4 Ω and R2 = 2 Ω, what is the current running through R1 and R2?
Phantasy [73]
Total resistance=R1+ R2= 6Ω
Voltage=12v
Current =\frac{voltage}{resistance}
Current= 2A
In a series circuit, equal current passes through every resistance.
Answer is option A
7 0
3 years ago
If an electron moves in a circle of radius 21 cm perpendicular to a B field of 0.4 T, what are the speed of the electron and the
kodGreya [7K]

Answer:

a)

v = 4.048 *10^6 m/s

b)  

Angular frequency =  1.92 * 10^7

Explanation:

As we know

v =  \frac{qBr}{m}

q is the charge on the electron = 3.2 * 10^{-19} C

B is the magnetic field in Tesla = 0.4 T

r is the radius of the circle = 0.21 m

mass of the electrons = 6.64 * 10^{-27} Kg

a)

Substituting the given values in above equation, we get -

v = \frac{3.2 * 10^{-19}*0.4*0.21}{6.64 * 10^{-27}} \\v = 4.048 *10^6m/s

b)  

Angular frequency =

\frac{4.048 * 10^6 }{0.21} \\1.92 * 10^7

8 0
2 years ago
An object moving at a constant speed of 25 m/s is making a turn with a radius of curvature of 7 m (this is the radius of the "ki
prisoha [69]

Answer:

- 278.34 kg m/s^2

Explanation:

The rate of the change of momentum is the same as the force.

The force that an object feels when moviming in a circular motion is given by:

F = -mrω^2

Where ω is the angular speed and r is the radius of the circumference

Aditionally, the tangential velocity of the body is given as:

v = rω

The question tells us that

v = 25 m/s

r = 7m

mv = 78 kg m/s

Therefore:

m = (78 kg m/s) / (25 m/s) = 3.12 kg

ω = (25 m/s) / (7 m) = 3.57 (1/s)

Now, we can calculate the force or rate of change of momentum:

F = - (3.12 kg) (7 m)(3.57 (1/s))^2

F = - 278.34 kg m/s^2

4 0
3 years ago
What does the revolution of the moon do to it?
Degger [83]

Answer:

The Moon revolves or moves around the Earth in a path called its orbit and rotates, or spins, in space.

Explanation: The Moon's movements cause the phases of the Moon and the Earth's ocean tides.

7 0
3 years ago
Identify how scientists use radioactive isotopes by selecting the best answers from the drop-down menus. Archaeologists use radi
salantis [7]

Answer:

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6 0
3 years ago
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