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34kurt
3 years ago
15

Thinking Mathematically: Explore the quantitative dependencies of the acceleration upon the speed and the radius of curvature. T

hen answer the following questions. a. For the same speed, the acceleration of the object varies _____________ (directly, inversely) with the radius of curvature. b. For the same radius of curvature, the acceleration of the object varies _____________ (directly, inversely) with the speed of the object. c. As the speed of an object is doubled, the acceleration is __________________ (one-fourth, one-half, two times, four times) the original value. d. As the speed of an object is tripled, the acceleration is __________________ (one-third, one-ninth, three times, nine times) the original value. e. As the radius of the circle is doubled, the acceleration is __________________ (one-fourth, one-half, two times, four times) the original value. f. As the radius of the circle is tripled, the acceleration is __________________ (one-third, one-ninth, three times, nine times) the original value.
Physics
1 answer:
solong [7]3 years ago
6 0

The expression for the centripetal acceleration allows to find the results for the questions are:

A) The acceleration varies INVERSELY with the radius of curvature.

B) The acceleration varies DIRECTLY with the speed.

C) The acceleration becomes four times greater.

D) The acceleration becomes nine times greater.

E) The acceleration is reduced to half.

F) The acceleration is reduced to a third.

In circular motion there must be an acceleration towards the center of the circle, it is called cenripetal acceleration, in this case all the energy supplied to the system is used to change the direction of the speed even when its magnitude remains constant.

        a_c = \frac{v^2}{r}  

Where a_c the centripetal acceleration, v is the speed and r the radius of curvature of the circle.

Now we can answer the questions about centripetal acceleration.

A) For the same speed, the acceleration varies INVERSELY with the radius of curvature.

B) For the same radius of curvature the acceleration varies DIRECTLY with the speed.

C) The speed is doubled

         v = 2 v₀

         a_c = \frac{(2v_o)^2 }{r}  

         a_c = 4 \ \frac{v_o^2 }{r}  

The acceleration becomes four times greater than the original value

D) The speed is tripled

         v = 3 v₀

         a_c = 9 \frac{ v_o^2}{r}  

Acceleration becomes nine times greater than the original

E) the radius of curvature is doubled

        r = 2 r₀  

        a_c = \frac{v_o^2}{2 r_o }  

        a_c = \frac{1}{2}  a_o  

Acceleration is reduced to half the original value

F) The radius of curvature is tripled

       r = 3 r₀

       a_c = \frac{v_o^2 }{3 r_o}  \\ \\a_c = \frac{1}{3} a_o  

       

The acceleration is reduced to a third of the initial one.

In conclusion using the expression for the centripetal acceleration we can find the answers for the questions are:

A) The acceleration varies INVERSELY with the radius of curvature.

B) The acceleration varies DIRECTLY with the speed.

C) The acceleration becomes four times greater.

D) The acceleration becomes nine times greater.

E) The acceleration is reduced to half.

F) The acceleration is reduced to a third.

Learn more here: brainly.com/question/6082363

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oee [108]

Answer:

A. Their shape

Explanation:

The name clearly shows that the shape of these canals are semi-circular. The semi-circular canals consist of three tubes filled with fluid and located in the inner ear. They help to maintain balance and transmit impulses through the movement of the fluids. The impulses sent through these fluids are sent to the brain for interpretation.

The function of the canals are not indicated by the name, rather the shape is hinted through the name.

7 0
3 years ago
The radioactive element polonium decays according to the law given below where Q0 is the initial amount and the time t is measur
kogti [31]

Answer:

1280 mg

Explanation:

Radioactive  decay is a phenomenon that occurs when a certain isotope of an element, said to be radioactive, decays, turning into a lighter nucleus and emitting radiation + energy in the process.

The radioactive decay of this isotope of polonium is described by the equation

Q(t)=Q_0 2^{-\frac{t}{140}}

where

Q(t) is the amount of polonium left after time t

Q_0 is the amount of polonium t time t = 0

140 is the half-life of the polonium, in days (it is the time it takes for the initial element to halve its amount)

IN this problem, we know that:

After t = 560 days, the amount of polonium left is Q(t)=80 mg. Therefore, we can re-arrange the equation, substituting t = 560 d, and solve for Q_0 to find the initial amount of polonium:

Q_0 = Q(t) \cdot 2^{\frac{t}{140}}=(80)\cdot 2^{\frac{560}{140}}=1280 mg

5 0
3 years ago
my choice1A child pushes a toy truck up an inclined plane. The lifting force is...Select one:ut ofO a. the weight of the truck.O
mash [69]

When pushing a toy truck up an inclined plane, the force that makes the truck goes up is the force that the child uses to push the truck. (The force that pushes

Therefore the correct option is C.

4 0
1 year ago
A small candle is 38 cm from a concave mirror having a radius of curvature of 24 cm. (a) what is the focal length of the mirror?
Finger [1]
For a concave mirror, the radius of curvature is twice the focal length of the mirror:
r=2f
where f, for a concave mirror, is taken to be positive.

Re-arranging the formula we get:
f= \frac{r}{2}
and since the radius of curvature of the mirror in the problem is 24 cm, the focal length is
f= \frac{24 cm}{2} = 12 cm

8 0
4 years ago
A room has a volume of 160 m3. An air-conditioning system is to replace the air in this room every 21.3 minutes, using ducts tha
serious [3.7K]

Answer:

A. 0.204203928 m

b. 0.1443939822

Explanation:

Givens:

Volume (V) = 160 m^3

velocity 1 (v1) = 3.00 m/s

velocity 2 (v2) = 6.00 m/s

Time (t) = 21.3 minutes = 1278 seconds

Side length = ?

V = A*v*t

A = s^2

V = s^2*v*t

s= \sqrt{\frac{V}{v*t} }

A.

s = \sqrt{\frac{V}{v*t} } = \sqrt{\frac{160}{3.00*1278} } = 0.204203928 m

B.

s = \sqrt{\frac{V}{v*t} } = \sqrt{\frac{160}{6.00*1278} } = 0.1443939822 m

I hope this helped!! Have a good day.

7 0
3 years ago
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