The inequality which represents possible values of the expression 2+sqrt 10 by virtue of the given inequality; 3.1 < sqrt 10 < 3.2 as in the task content is; 5.1 < 2 + sqrt 10 < 5.2.
<h3>Which inequality correctly expresses the possible values of the expression; 2 + √10 as required in the task content?</h3>
It follows from the task content that the expression given is;
3.1 < sqrt 10 < 3.2
Since the given premises is an inequality, it follows that adding the same number to all parts of the inequality stills holds the inequality true.
Hence by adding 2 to all parts of the inequality, we have;
2 + 3.1 < 2 + sqrt 10 < 2 + 3.2
Therefore, we have;
5.1 < 2 + sqrt 10 < 5.2
Ultimately, 5.1 < 2 + sqrt 10 < 5.2 represent the possible values of the expression 2+sqrt 10 as given by the inequality 3.1 < sqrt 10 < 3.2.
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Answer:
its the steepness of two numbers on a graph - measures the steepness of the line. (what a slope is)
y=40x+10
Step-by-step explanation:
y=mx+b
I believe the answer will be 23in
Answer:
i need more info? it doesnt seem to make sense with just that..
Step-by-step explanation:
Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of draws necessary to get an ace. Find E(X) is given in the following way
Step-by-step explanation:
- From a standard deck of cards, one card is drawn. What is the probability that the card is black and a
jack? P(Black and Jack) P(Black) = 26/52 or ½ , P(Jack) is 4/52 or 1/13 so P(Black and Jack) = ½ * 1/13 = 1/26
- A standard deck of cards is shuffled and one card is drawn. Find the probability that the card is a queen
or an ace.
P(Q or A) = P(Q) = 4/52 or 1/13 + P(A) = 4/52 or 1/13 = 1/13 + 1/13 = 2/13
- WITHOUT REPLACEMENT: If you draw two cards from the deck without replacement, what is the probability that they will both be aces?
P(AA) = (4/52)(3/51) = 1/221.
- WITHOUT REPLACEMENT: What is the probability that the second card will be an ace if the first card is a king?
P(A|K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been removed.
- WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick a card, write down what it is, then put it back in the deck and draw again. To find the P(QQQ), we find the
probability of drawing the first queen which is 4/52.
- The probability of drawing the second queen is also 4/52 and the third is 4/52.
- We multiply these three individual probabilities together to get P(QQQ) =
- P(Q)P(Q)P(Q) = (4/52)(4/52)(4/52) = .00004 which is very small but not impossible.
- Probability of getting a royal flush = P(10 and Jack and Queen and King and Ace of the same suit)
