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sweet-ann [11.9K]
3 years ago
5

Which of the following describes a positive feedback loop?

Biology
2 answers:
natka813 [3]3 years ago
5 0
The correct answer to the question being presented above would be the third sentence of the choices. The situation wherein '<span>a pregnant woman begins to go into labor, the body sends hormones that increase the intensity of the labor contractions.' describes a positive feedback loop.</span>
ehidna [41]3 years ago
4 0

Answer;

An example of positive feedback loop is;

-When a pregnant woman begins to go into labor, the body sends hormones that increase the intensity of the labor contractions.

Explanation;

-Feedback loops are therefore the process whereby a change to the system results in an alarm which will trigger a certain result. The result will  then either increase the change to the system or reduce it to bring the system back to normal.

-Feedback loops are important because they allow living organisms to maintain homeostasis (maintenance of internal environment of the body constant).

-A positive feedback loop occurs in nature when the product of a reaction leads to an increase in that reaction.  It moves a system further away from the target of equilibrium, by amplifying the effects of a product or event and occurs when something needs to happen quickly.

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What is the probability that the first offspring from the cross listed below will be heterozygous for all loci?
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Answer and Explanation:

<u>Cross:</u> aa Bb dd Ee x AA bb Dd Ee

We can calculate the probability of getting heterozygous individuals in the progeny by using the <u>product rule</u>. Assuming that these four genes <u>assort independently</u> (<em>events that occur independently from each other</em>), we can infer that the F1 will have the next genotypic proportions for each gene:

1) aa     x     AA

F1) 4/4=1 Aa

2) Bb    x    bb

F1) ½ bb

     ½ Bb

3) dd    x    Dd

F1) ½ dd

     ½ Dd

4) Ee    x    Ee

F1) ¼ EE

    2/4 = ½ Ee

     ¼ ee

So, to know what the probability is that the F1 of being heterozygous for all loci, we must multiply the respective individual probabilities of getting a heterozygous genotype, like this:  

1 Aa   x   ½ Bb   x    ½ Dd    x    ½ Ee = 1/8 AaBbDdEe

                                 

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