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liq [111]
3 years ago
12

What's the answer ?????? Someone please help

Mathematics
1 answer:
Doss [256]3 years ago
5 0
A´(-2,-4) B´(-3,-7) C´(-1,-8) D´(1,-6)
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Please anyone answer me
ollegr [7]

Let's divide the shaded region into two areas:

area 1: x = 0 ---> x = 2

ares 2: x = 2 ---> x = 4

In area 1, we need to find the area under g(x) = x and in area 2, we need to find the area between g(x) = x and f(x) = (x - 2)^2. Now let's set up the integrals needed to find the areas.

Area 1:

A\frac{}{1}  = ∫g(x)dx =  ∫xdx =  \frac{1}{2}  {x}^{2}  | \frac{2}{0}  = 2

Area 2:

A\frac{}{2}  = ∫(g(x) - f(x))dx

= ∫(x -  {(x - 2)}^{2} )dx

=  ∫( - {x}^{2}  + 5x - 4)dx

= ( - \frac{1}{3}{x}^{3} +   \frac{5}{2} {x}^{2}  - 4x)   | \frac{4}{2}

= 2.67 - ( - 0.67) = 3.34

Therefore, the area of the shaded portion of the graph is

A = A1 + A2 = 5.34

3 0
3 years ago
Plz answer ASAP I don't understand it easy math
Rashid [163]

Answer:

its not there

Step-by-step explanation:

because i saw it

3 0
3 years ago
PLEASE PLEASE PLEASE ​
Scilla [17]

Answer: The first one

6 0
3 years ago
Hi. Please I need help with this :
ki77a [65]

Answer:

1.79553

Step-by-step explanation:

Step 1: Write expression

log₁₀(√(69.5² - 30.5²))

Step 2: Evaluate square root

log(√(4830.25 - 930.25))

log(√3900)

log(62.45)

Step 3: Find log

log₁₀ (or log)

log(62.45) = 1.79553

-------------------------------------

To use the table method. we find values that are easily evaluated by log₁₀

log₁₀(10) = 1

log₁₀(50) = 1.69897

log₁₀(100) = 2

So we know that log₁₀(62.45) is between 1 and 2 and greater that 1.69897.

3 0
3 years ago
Jupiter's orbit is about 3×10^9 miles and Earth's orbit is about 6×10^8 miles. How many times longer is Jupiter's orbit than Ear
Tasya [4]

Answer:

5

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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