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Ksenya-84 [330]
3 years ago
9

Yo can someone help me

Mathematics
1 answer:
Neporo4naja [7]3 years ago
3 0

Answer:

Graph #2

Step-by-step explanation:

I would use Desmos for this, makes it easier to find out which graph is for the equation.

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Write 54 + 63 as the product of the GCF of 54 and 63 and another sum
levacccp [35]

Answer:

9*(6+7)

Step-by-step explanation:

First, we have to find the Greatest Common Factor (GCF), to do this we have to see all the factors of 54 and 63 and find the greatest factor that they have in common.

Factors of 54

1,2,3,6,9,18,27,54

Factors of 63

1,3,7,9,21,63

The GCF is 9 because is the greatest factor that is common to both numbers.

Now we have to divide 54/9 and 63/9

54/9 = 6

63/9 = 7

So now we can write the product of the GCF and another sum:

9*(6+7)

<em>We can prove this by solving both expressions:</em>

<em>54+63 = 9*(6+7)</em>

<em>117 = 9*13</em>

<em>117 = 117 </em>

<em>The results are equal so we prove it is right.</em>

8 0
2 years ago
Read 2 more answers
How do i find answes to endjunity geomatry
konstantin123 [22]

Answer:

Hey there !

Under the More button, select View Course Structure.

Find the lesson to view the assessment answers. Click Quiz Answers.

All the assessment questions related to the lesson are found in the pop-up window. To view a question and answer, select a question number.

5 0
3 years ago
V = X timesY times Z solve for x
N76 [4]

Answer:

X = V/(YZ)

Step-by-step explanation:

V=XYZ

Division property of equality

V/(YZ) = X

Symmetric property of equality

X= V/(YZ)

8 0
3 years ago
What is the next three terms for 0.25, 0.5, 1
EleoNora [17]
1.75, 2.75, 4

hope this helps!
7 0
2 years ago
Read 2 more answers
The National Assessment of Educational Progress (NAEP) includes a mathematics test for eighth-graders. Scores on the test range
LiRa [457]

Answer:

Its standard deviation is 3.79.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\sigma = 125, n = 1089

So

s = \frac{125}{\sqrt{1089}} = 3.79

Its standard deviation is 3.79.

7 0
3 years ago
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