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2 years ago

Y’all I need a lot of help please help me and please show work

Mathematics

1 answer:

Nadya [2.5K]2 years ago

4 0

Answer:

Step-by-step explanation:

no of total groups = 2+6+4=12

so in total there are 12 groups

each have equal number of members

so the answer is the number that is not a factor of 12

i hope this help you

this is quite high order thinking question

so don't know about the steps

if you understood then you may write the steps yourself

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Mrs. Jackson gives the table below to her students.

krek1111 [17]

M= 20 because the rate of change is -3.

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2 years ago

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dsp73

Answer:

109

Step-by-step explanation:

81-19 is 62. if you add 109 then you could do 109-19 is 90

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2 years ago

Can I get help with finding the Fourier cosine series of F(x) = x - x^2

trapecia [35]

Assuming you want the cosine series expansion over an arbitrary symmetric interval $[-L,L]$ , $L\neq0$ , the cosine series is given by

$f_C(x)=\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos nx$

You have

$a_0=\displaystyle\frac1L\int_{-L}^Lf(x)\,\mathrm dx$
$a_0=\dfrac1L\left(\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{x=-L}^{x=L}$
$a_0=\dfrac1L\left(\left(\dfrac{L^2}2-\dfrac{L^3}3\right)-\left(\dfrac{(-L)^2}2-\dfrac{(-L)^3}3\right)\right)$
$a_0=-\dfrac{2L^2}3$

$a_n=\displaystyle\frac1L\int_{-L}^Lf(x)\cos nx\,\mathrm dx$

Two successive rounds of integration by parts (I leave the details to you) gives an antiderivative of

$\displaystyle\int(x-x^2)\cos nx\,\mathrm dx=\frac{(1-2x)\cos nx}{n^2}-\dfrac{(2+n^2x-n^2x^2)\sin nx}{n^3}$

and so

$a_n=-\dfrac{4L\cos nL}{n^2}+\dfrac{(4-2n^2L^2)\sin nL}{n^3}$

So the cosine series for $f(x)$ periodic over an interval $[-L,L]$ is

$f_C(x)=-\dfrac{L^2}3+\displaystyle\sum_{n\ge1}\left(-\dfrac{4L\cos nL}{n^2L}+\dfrac{(4-2n^2L^2)\sin nL}{n^3L}\right)\cos nx$

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2 years ago

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Svetlanka [38]

75% of the gallon of milk is left

16/16-4/16=12/16

12/16=3/4=0.75

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3 years ago

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Hitman42 [59]

Answer: 100cm^2

Step-by-step explanation:

i took the test