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AfilCa [17]
3 years ago
10

The length of each side of the square is decreased by 2 inches, so the perimeter is now 48 inches . What was the original length

of each side of the square
Mathematics
1 answer:
Jet001 [13]3 years ago
5 0
X=original length of each side of the square.
perimeter: sum of all sides=4(length of the side)
The length of each side of the new square will be= (x-2)
we can suggest this equation:

4(x-2)=48

We solve this equation:
4(x-2)=48
4x-8=48
4x=48+8
4x=56
x=56/4
x=14

Answer: the original length of each side of the square would be 14 in. 

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Jessie runs 8 yards every 2 seconds. How many feet does Jessie run in 10 seconds?
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Answer please cuz I'm very confused
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5x + 3y = - 53

the equation of a line in ' slope- intercept form ' is y = mx + c

where m is the slope and c the y-intercept

rearrange 3x - 5y = - 15 into this form to obtain m → (subtract 3x from both sides)

- 5y = - 3x - 15 → divide all terms by - 5 )

y = \frac{3}{5} x + 3 → in slope-intercept form with m = \frac{3}{5}

given a line with slope m then the slope m₁ of a line perpendicular to it is

m₁ = - \frac{1}{m} = - 1 ÷ \frac{3}{5} = - \frac{5}{3}

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to find c substitute ( - 7, - 6) into the partial equation

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6 0
3 years ago
8. Write the equation of the line that is parallel to the line 2x + 5y = 15 and passes through the
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Answer:

\sf y = \bold -\frac{2}{5} x -3

Explanation:

part A identification for slope:

\sf 2x + 5y = 15

\sf 5y = -2x + 15

\sf y = \frac{-2x + 15}{5}

\sf y = -\frac{2 }{5} x+3

comparing with slope intercept form: y = mx + b

we can find that here the slope is \bold -\frac{2}{5}

part B, solving the equation:

if the line is parallel, then the slope will be same.

given coordinates: ( - 10, 1 )

using the equation:

y - y₁ = m( x - x₁ )

\sf y - 1 = \bold -\frac{2}{5} (x --10)

\sf y = \bold -\frac{2}{5} x -4 + 1

\sf y = \bold -\frac{2}{5} x -3

Extra information:

check the image below. this proves that the line is parallel and passes through point (-10, 1). the blue line is question line and red the answer line.

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