Let
x = number of apples.
y = number of oranges.
we have to write the following equation to represent the problem:
4x + 6y = 15
To satisfy the equation, Jon must have used
x = 2.25
y = 1
Substituting
4 (2.25) +6 (1) = 15
9 + 6 = 15
answer
Jhon used 2.25kg of apple and 1kg of orange to make the salad.
Note: Since the problem does not have any other restrictions, there may be several apple and orange combinations that cost $ 15 per salad.
Answer:
f(10) = 8
Step-by-step explanation:
f(x) = 4(x - 8)
Let x = 10
f(10) = 4 ( 10-8)
= 4 ( 2)
= 8
◆ Define the variables:
Let the calorie content of Candy A = a
and the calorie content of Candy B = b
◆ Form the equations:
One bar of candy A and two bars of candy B have 774 calories. Thus:
a + 2b = 774
Two bars of candy A and one bar of candy B contains 786 calories
2a + b = 786
◆ Solve the equations:
From first equation,
a + 2b = 774
=> a = 774 - 2b
Put a in second equation
2×(774-2b) + b = 786
=> 2×774 - 2×2b + b = 786
=> 1548 - 4b + b = 786
=> -3b = 786 - 1548
=> -3b = -762
=> b = -762/(-3) = 254 calorie
◆ Find caloric content:
Caloric content of candy B = 254 calorie
Caloric content of candy A = a = 774 - 2b = 774 - 2×254 = 774 - 508 = 266 calorie
She distributed the 4 to the 2x-1, giving her 9+ 8x -4. she subtracted 8x from both sides leaving her with 4=9-4 which is the same as 4=5
