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vitfil [10]
3 years ago
8

How to factoring quadratics by grouping 2x^2-5x+3

Mathematics
1 answer:
charle [14.2K]3 years ago
8 0
There aren't enough terms to factor this by grouping; you need at least four, at least as far as i know? trinomials are usually pretty easily factored by trial and error

(2x - 3)(x - 1)

is how it factors down. you know that two only has two factors (2 and 1), so you always have (2x +_) and (1x +_) for trinomials beginning with 2x^2. from there, i usually just plug in factors of your constant (3, in this case) and see which ones fit the empty spaces!!
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Sorry for the bad handwriting but the answer is -23<3x
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Factored completely, the expression 16k^2 + 16k + 4 is equivalent to
sergeinik [125]
16k^2 + 16k + 4

We can first start off by dividing every term by 4:

4 (4k^2 + 4k + 1)

to factor, you find which two number you can multiply with each other to get the middle term. So 2 and 2 to get 4. Substitute that into the equation

4 (4k^2 + 2k + 2k + 1)

the first two terms become a group and the last 2 terms become a group. Factor like terms out of the two groups.

4 (2k (2k + 1) + 1 (2k + 1))

4 (2k + 1)(2k + 1)
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4 years ago
sarah eats the same number of pieces of candy from a bowl on her counter each day. the expression 64 – 4x shows how many pieces
ipn [44]
The number 4 represents the number of pieces of candy she eats each day.
7 0
4 years ago
Read 2 more answers
If a line has a slope of -5/6 a line that is parallel has a slope of what
attashe74 [19]

Hello there! :)

Parallel lines have the same slope.

We are given that one line has a slope of -5/6.

The line parallel to it has a slope of -5/6 as well.

Hope it helps.

Please mark brainliest.

~An emotional teen who helps others with joy

Good luck.

7 0
2 years ago
Please show your work and explain it.
Maru [420]

Answer:

f(x)=\dfrac{x+2}{2(x-2)}

Step-by-step explanation:

Remember when you divide fractions, you need to get the reciprocal of the divisor and multiply. So your first simplification would be:

\dfrac{x^2+4x+4}{x^2-6x+8}\div\dfrac{6x+12}{3x-12}\\\\=\dfrac{x^2+4x+4}{x^2-6x+8}\times\dfrac{3x-12}{6x+12}\\\\=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}

Next we factor what we can so we can further simplify the rest of the equation:

=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}\\\\=\dfrac{(x+2)(x+2)(3x-12)}{(x^2-6x+8)(6(x+2))}\\\\

We can now cancel out (x+2)

=\dfrac{(x+2)(3x-12)}{(x^2-6x+8)(6)}

Next we factor out even more:

=\dfrac{(x+2)(3)(x-4)}{(x-2)(x-4)(6)}

We cancel out x-4 and reduce the 3 and 6 into simpler terms:

=\dfrac{(x+2)(1)}{(x-2)(2)}

And we can now simplify it to:

=\dfrac{x+2}{2(x-2)}

6 0
4 years ago
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