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Contact [7]
3 years ago
14

Do all squares have two pairs of parallel sides?Explan

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
7 0

Yes any square is also a parallelogram, but not the other way around (some parallelograms are not squares). In other words, any square is a parallelogram.

If you draw a Venn Diagram, the set of squares will be entirely inside the set of parallelograms.

This is because any rhombus is also a parallelogram, and the same applies to rectangles as well. A square is the combination of a rhombus and rectangle.

Rhombus = four sided figure where all sides are equal

Rectangle = four sided figure where all angles are equal to 90 degrees

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Math help mee plzzzzzz THERE IS A ATTACHMENT SO WAIT AT LEAST 30 SECONDS PLZZZZME
VLD [36.1K]
I hope this helps you


25$-14$=11$ a month

6 month 6.11$=66$
7 0
3 years ago
A college surveys local businesses about the importance of students as customers. The college chooses 150 businesses at
GenaCL600 [577]

The proportion of businesses who did not respond = 54.67%

Given : Total businesses = 150

Businesses responded = 68

Businesses did not respond =  150- 68 = 82

The proportion of businesses who did not respond =

82/150 x 100

54.67%

8 0
3 years ago
Does anyone know how to do this help please
statuscvo [17]

Answer:

\boxed{\begin{array}{c|c|c|c|c|c|c|c} \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}

Step-by-step explanation:

A quadratic function is given to us . And we need to fill out the table by using the function . The given function is ,

\rm\implies y = x^2+x - 6

Here we need to substitute the different values of x , to get the different values of y.

<u>Put</u><u> </u><u>x </u><u>=</u><u> </u><u>-</u><u>3</u><u> </u><u>:</u><u>-</u><u> </u>

\rm\implies y = 3^2-3-6\\

\rm\implies y = 9 - 3 - 6 \\

\rm\implies y = 0

<u>Put </u><u>x </u><u>=</u><u> </u><u>-</u><u>2</u><u> </u><u>:</u><u>-</u><u> </u>

\rm\implies y = 2^2-2-6\\

\rm\implies y = 4 -2-6\\

\rm\implies y = -4

<u>Put</u><u> </u><u>x </u><u>=</u><u> </u><u>-</u><u>1</u><u> </u><u>:</u><u>-</u><u> </u>

\rm\implies y = -1^2-1-6\\

\rm\implies y = 1 -1-6 \\

\rm\implies y = -6

<u>Put </u><u>x </u><u>=</u><u> </u><u>1</u><u> </u><u>:</u><u>-</u><u> </u>

\rm\implies y = 1^2+1-6\\

\rm\implies y = 2 -6

\rm\implies y = -4

<u>Put </u><u>x </u><u>=</u><u> </u><u>2</u><u> </u><u>:</u><u>-</u><u> </u>

\rm\implies y = 2^2+2-6\\

\rm\implies y = 4 +2-6\\

\rm\implies y = 2

<u>Put </u><u>x </u><u>=</u><u> </u><u>3 </u><u>:</u><u>-</u><u> </u>

\rm\implies y = 3^2+3-6\\

\rm\implies y = 9 +3-6\\

\rm\implies y = 6

<u>Final </u><u>table</u><u> </u><u>:</u><u>-</u><u> </u>

\boxed{\begin{array}{c|c|c|c|c|c|c|c} \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}

7 0
3 years ago
How do I solve this?
Aleksandr-060686 [28]
First you have to set up your equation. 5x+80 and x+15. 
8 0
3 years ago
Read 2 more answers
Please help!!! I’ll mark brainliest!! (Look at picture)
Svetllana [295]

Answer:

\huge\boxed{\sf (x*4) + (x*5) = 54}

Step-by-step explanation:

\sf x(4+5) = 54\\\\Applying \ distributive \ property\\\\(x*4) + (x*5) = 54\\\\Distributive\ Property\ is:\\\\A(B+C) = (A*B)+(A*C)\\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
4 0
3 years ago
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