All categories

3 years ago

F(x) = 3x + 1 f(2)=?

Mathematics

1 answer:

ANEK [815]3 years ago

7 0

Answer: 7

Step-by-step explanation:

f(x) 3x+1

f(2) = 3(2) +1

f(2) = 6+1

= 7

You might be interested in

I need help on this what's the answer for it 2/7 + 2/3 =

slava [35]

20/21 is the answer to your problem.

3 0

3 years ago

Read 2 more answers

Simplify to create an equivalent expression of 2(−n−3)−7(5+2n)

musickatia [10]

<h3>Answer: -16n-41</h3>

Work Shown:

2(-n-3) -7(5+2n)

2(-n)+2(-3) - 7(5)-7(2n) ... distribute

-2n - 6 - 35 - 14n

(-2n-14n) + (-6-35)

-16n - 41

6 0

3 years ago

What are the dimensions of a rectangular box with a volume of 50b 3 + 75b2 - 2b - 3?

Inessa [10]

Answer:

$\large\boxed{(2b+3)\times(5b-1)\times(5b+1)}$

Step-by-step explanation:

The formula of a volume of a rectangular box:

$V=lwh$

l - lenght

w - width

h - height

$V=50b^3+75b^2-2b-3=25b^2(2b+3)-1(2b+3)\\\\=(2b+3)(25b^2-1)=(2b+3)(5^2b^2-1^2)\\\\=(2b+3)\bigg((5b)^2-1^2\bigg)\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=(2b+3)(5b-1)(5b+1)$

Therefore the dinemsions of thisp prism are:

$(2b+3)\times(5b-1)\times(5b+1)$

5 0

2 years ago

Read 2 more answers

If <img src="https://tex.z-dn.net/?f=%5Crm%20%5C%3A%20x%20%3D%20log_%7Ba%7D%28bc%29" id="TexFormula1" title="\rm \: x = log_{a}(

timama [110]

Use the change-of-basis identity,

$\log_x(y) = \dfrac{\ln(y)}{\ln(x)}$

to write

$xyz = \log_a(bc) \log_b(ac) \log_c(ab) = \dfrac{\ln(bc) \ln(ac) \ln(ab)}{\ln(a) \ln(b) \ln(c)}$

Use the product-to-sum identity,

$\log_x(yz) = \log_x(y) + \log_x(z)$

to write

$xyz = \dfrac{(\ln(b) + \ln(c)) (\ln(a) + \ln(c)) (\ln(a) + \ln(b))}{\ln(a) \ln(b) \ln(c)}$

Redistribute the factors on the left side as

$xyz = \dfrac{\ln(b) + \ln(c)}{\ln(b)} \times \dfrac{\ln(a) + \ln(c)}{\ln(c)} \times \dfrac{\ln(a) + \ln(b)}{\ln(a)}$

and simplify to

$xyz = \left(1 + \dfrac{\ln(c)}{\ln(b)}\right) \left(1 + \dfrac{\ln(a)}{\ln(c)}\right) \left(1 + \dfrac{\ln(b)}{\ln(a)}\right)$

Now expand the right side:

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} \\\\ ~~~~~~~~~~~~+ \dfrac{\ln(c)\ln(a)}{\ln(b)\ln(c)} + \dfrac{\ln(c)\ln(b)}{\ln(b)\ln(a)} + \dfrac{\ln(a)\ln(b)}{\ln(c)\ln(a)} \\\\ ~~~~~~~~~~~~ + \dfrac{\ln(c)\ln(a)\ln(b)}{\ln(b)\ln(c)\ln(a)}$

Simplify and rewrite using the logarithm properties mentioned earlier.

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} + \dfrac{\ln(a)}{\ln(b)} + \dfrac{\ln(c)}{\ln(a)} + \dfrac{\ln(b)}{\ln(c)} + 1$