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Wittaler [7]
3 years ago
5

Lucy went to the store with $50. She bought a pair of jeans for $14.99, three shirts for $4 each, and a bag of Cheetos for $2.25

. While at the store, she found another $10 in the bottom of her purse. How much money did Lucy have when she left the store?
Mathematics
2 answers:
Soloha48 [4]3 years ago
8 0
$30.76 is your answer!!!
jekas [21]3 years ago
3 0

Answer:

$30.76

Step-by-step explanation:

Subtract the costs of her purchases from her total of 50:

50 - (14.99 + 3(4) + 2.25)

50 - (14.99 + 12 + 2.25)

50 - 29.24

= 20.76

Now, add the $10 that she found to this:

20.76 + 10

= 30.76

So, when she left the store, Lucy had $30.76

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Step-by-step explanation:

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Where should the point P be chosen on line segment AB so as to maximize the angle θ? (Assume a = 4 units, b = 5 units, and c = 9
taurus [48]
From the figure, let the distance of point P from point A on line segment AB be x and let the angle opposite side a be M and the angle opposite side c be N.

Using pythagoras theorem,
\tan M= \frac{a}{b-x} \\ \\ M=\tan^{-1}\left(\frac{a}{b-x}\right)
and
\tan N= \frac{c}{x} \\ \\ N=\tan^{-1}\left(\frac{c}{x}\right)

Angle θ is given by
\theta=180-M-N \\  \\ =180-\tan^{-1}\left(\frac{a}{b-x}\right)-\tan^{-1}\left(\frac{c}{x}\right)

Given that a = 4 units, b = 5 units, and c = 9 units, thus
\theta=180-\tan^{-1}\left(\frac{4}{5-x}\right)-\tan^{-1}\left(\frac{9}{x}\right)

To maximixe angle θ, the differentiation of <span>θ with respect to x must be equal to zero.
i.e.
\frac{d\theta}{dx} = -\frac{4}{x^2-10x+41} + \frac{9}{x^2+81} =0 \\  \\ -4(x^2+81)+9(x^2-10x+41)=0 \\  \\ -4x^2-324+9x^2-90x+369=0 \\  \\ 5x^2-90x+45=0 \\  \\ x^2-18x+9=0 \\  \\ x=9\pm6 \sqrt{2}

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Therefore, The distance from A of point P, so that </span>angle θ is maximum is 0.51 to two decimal places.
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