Procedure:
1) calculate the number of diferent teams of four members that can be formed (with the ten persons)
2) calculate the number of teams tha meet the specification (two girls and two boys)
3) Divide the positive events by the total number of events: this is the result of 2) by the result in 1)
Solution
1) the number of teams of four members that can be formed are:
10*9*8*7 / (4*3*2*1) = 210
2) Number of different teams with 2 boys and 2 girls = ways of chosing 2 boys * ways of chosing 2 girls
Ways of chosing 2 boys = 6*5/2 = 15
Ways of chosing 2 girls = 4*3/2 = 6
Number of different teams with 2 boys and 2 girls = 15 * 6 = 90
3) probability of choosing one of the 90 teams formed by 2 boys and 2 girls:
90/210 = 3/7
Answer:
65.4
Step-by-step explanation:
60*.09 = 5.4
60+5.4 = 65.4
Answer:
12.5%
Step-by-step explanation:
I warn you, I'm not positive I'm correct.
First I added 8+10+6 and got 24
I divided that by 3 and got 8
I divided 100 by 8 because if you cross multiply 1/8 and x/100 you would get 8x = 100
100 ÷ 8 = 12.5
So I got 12.5%
Answer:
you would problely need to look it up on google
Step-by-step explanation:
64^x=16^x-1====> Make the bases the same
4^3(x)=4^2(x-1)=> Solve for x by bringing down the exponent without the base.
3(x)=2(x-1)=====> Distribute
3x=2x-2======> Now solve for x
3x = 2x-2
-2x -2x
x=-2
Therefore x is negative two
