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Fudgin [204]
3 years ago
11

Please help. Not my strongest subject

Physics
1 answer:
Mars2501 [29]3 years ago
4 0
A) You'll notice from "c)" that the distance the object travelled was 75m, so you get V_a_v_e_r_a_g_e = 75m/15s = 5 m/s.

b) a = dV/dT, so a = (0-10)/15 and then you get a = -2/3 m/s ^{2}.

c) S = S_0 + V_0T + 0,5aT^2 and you get S = 10T - (2/6)T^2 and you plug in T = 15s and you'll get S = 75m
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A car in an amusement park ride rolls without friction around a track (Fig. P7.42). The hB car starts from rest at point A at a
MrRissso [65]

Answer:

h>\dfrac{5}{2}R

Explanation:

Given that

Height = h

Radius = R

From energy conservation

KE_A+U_A=KE_B+U_B

At point B

The minimum speed to complete the   the circle

V_B=\sqrt{gR}\ m/s

So the kinetic energy at point B

KE_B=\dfrac{1}{2}mV^2

KE_B=\dfrac{1}{2}mgR

KE_A+U_A=KE_B+U_B

0+mgh=\dfrac{1}{2}mgR+2mgR

Without falling off at the top (point B)

0+mgh>\dfrac{1}{2}mgR+2mgR

mg(h-2R)>\dfrac{1}{2}mgR

g(h-2R)>\dfrac{1}{2}gR

h>\dfrac{5}{2}R

6 0
4 years ago
Please left home at 8 AM to spend the day at in amusement park. He arrived at the park, which was 150 KM from his house, at 10 A
antiseptic1488 [7]

Answer:

v=\frac{150km}{2h}=75\frac{km}{h}

Explanation:

We can use the equation for the speed

v=\frac{x}{t}

where x is the distance and t the time. In this case we know that the time spent was 2 hours and the distance was 150km. By replacing we have

v=\frac{150km}{2h}=75\frac{km}{h}

I hope this useful for you

regards

3 0
3 years ago
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