Biodiversity is defined as

A 30000 grams boy is riding a merry-go-round with a radius of 600 cm. What is the centripetal force and acceleration on the boy

irga5000 [103]

Answer:

centripetal force is calculated by mass(kg) × tangetial velocity(m/s) ÷ radius (m)

Explanation:

so 30000g= 30kg

50km/h = 13.88m/s

600cm= 6m

30×13.88÷6= 69.4N

N= Newton's

hope this helps.

btw I'm 16 and love physics so I tried my best in this hope it went well!!

7 0

3 years ago

A 70 kg base runner begins his slide into second base while moving at a speed of 4.35 m/s. He slides so that his speed is zero j

sladkih [1.3K]

Answer

given,

Mass of the runner, M = 70 Kg

speed of the runner on the second base = 4.35 m/s

speed at the base = 0 m/s

Acceleration due to gravity,g = 9.8 m/s²

a) magnitude of mechanical energy lost

Mechanical energy lost is equal top gain in kinetic energy

$ME_{Lost}=\dfrac{1}{2}mv^2$

$ME_{Lost}=\dfrac{1}{2}\times 70\times 4.35^2$

$ME_{Lost}=662.29\ J$

b) Work done = Force x displacement

W = F. x

F = μ mg

W = μ mg . x

Work done is equal to 662.29 J

$x=\dfrac{W}{\mu m g}$

using the coefficient of the friction,μ = 0.7

$x=\dfrac{662.29}{ 0.7\times 70\times 9.8}$

x = 1.38 m

Hence, the runner will slide to 1.38 m.

3 0

3 years ago

The engine starter and a headlight of a car are connected in parallel to the 12.0-V car battery. In this situation, the headligh

stepladder [879]

Answer:

The total power they will consume in series is approximately 2.257 W

Explanation:

The connection arrangement of the headlight and the engine starter = Parallel to the battery

The voltage of the battery, V = 12.0 V

The power at which the headlight operates in parallel, $P_{headlight}$ = 38 W

The power at which the kick starter operates in parallel, $P_{kick \ starter}$ = 2.40 kW

We have;

P = V²/R

Where;

R = The resistance

V = The voltage = 12 V (The voltage is the same in parallel circuit)

For the headlight, we have;

R₁ = V²/ $P_{headlight}$ = 12²/38 = 72/19

R₁ = 72/19 Ω

For the kick starter, we have;

R₂ = V²/ $P_{kick \ starter}$ = 12²/2.4 = 60

R₂ = 60 Ω

When the headlight and kick starter are rewired to be in series, we have;

Total resistance, R = R₁ + R₂

Therefore;

R = ((72/19) + 60) Ω = (1212/19) Ω

The current flowing, I = V/R

∴ I = 12 V/(1212/19) Ω = (19/101) A

We note that power, P = I²R

In the series connection, we have;

$P_{headlight}$ = I² × R₁

∴ $P_{headlight}$ = ((19/101) A)² × 72/19 Ω = 1368/10201 W ≈ 0.134 W

The power at which the headlight operates in series, $P_{headlight, S}$ ≈ 0.134 W

$P_{kick \ starter}$ = ((19/101) A)² × 60 Ω = 21660/10201 W ≈ 2.123 W

The power at which the kick starter operates in series, $P_{kick \ starter, S}$ ≈ 2.123 W

The total power they will consume, $P_{Total}$ = $P_{headlight, S}$ + $P_{kick \ starter, S}$

Therefore;

$P_{Total}$ ≈ 0.134 W + 2.123 W = 2.257 W

4 0

3 years ago

In his famous race, a hare runs for a while, takes a nap, and then resumes running until he reaches the finish line. His total d

notka56 [123]

.6 MPM
T = Time
D = Distances
S = Speed

to get speed you Divide your Distances by Your time
hope I helped! :P

7 0

3 years ago

If Tony and Tanya both run at the same speed and in the same direction and they both run for the same amount of time, what can y

Marina86 [1]

Answer: They travel equal distances

Explanation:

Distance is amount of space covered from one point to another. It is measured in metres. Distance = speed x time taken

In this case,

- Since Tony and Tanya both run at the same speed: let speed = b

- Also, both run for the same amount of time: let time = c

Therefore, distance covered by Tony and Tanya = speed x time taken

Distance = b x c

Distance = bc (i.e Tony travelled a distance of bc, so also Tanya)

8 0

3 years ago