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jek_recluse [69]
3 years ago
9

M 1 N= 1 kg m 82 Acceleration = m/s2 PLEASE HELP MEE ?!?!?

Physics
2 answers:
victus00 [196]3 years ago
7 0

Answer:

do you speak Spanish?? well I'll show you 1 Kg where the m is and s / ² are you going to take it where Mass m Kg they are giving you an acceleraton clue

Tatiana [17]3 years ago
6 0

Explanation:

Force = mass × acceleration

force /acceleration =mass

20N /2ms^2=mass

Mass =10kg

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Si un movil parte del reposo logrando una aceleracion de 5 metros por segundo al cuadrado durante 8 segundos calcular la velocid
Komok [63]

Answer:

Velocidad final, V = 40 m/s

Explanation:

Dados los siguientes datos;

Aceleración = 5 m/s²

Velocidad inicial = 0 m/s (ya que comienza desde el reposo)

Tiempo = 8 segundos

Para encontrar la velocidad final, usaríamos la primera ecuación de movimiento;

V = U + at

Dónde;

  • V es la velocidad final.
  • U es la velocidad inicial.
  • a es la aceleración.
  • t es el tiempo medido en segundos.

Sustituyendo en la fórmula, tenemos;

V = 0 + 5*8

V = 0 + 40

V = 40

<em>Velocidad final, V = 40 m/s</em>

6 0
3 years ago
A heliocentric system is _____-centered.<br><br> Milky Way<br> Earth<br> Moon<br> Sun
madreJ [45]

Answer: Sun

Explanation:

7 0
3 years ago
Read 2 more answers
Please help on this physics question?
Llana [10]
I think it would be D.
3 0
3 years ago
Read 2 more answers
Pls help with either of these I will give up brainliest
Contact [7]

Answer:

1. The bird close to the center

2. 4/25 of the original force.

Explanation:

1. Tangential velocity is v=w*d (in m/s), where w is the rotational speed, commonly denoted as the letter omega (in radians per second). d is the distance from the center of the rotating object to the position of where you would like to calculate the velocity (in meters).

As we can note, the furthest from the center we are calculating the velovity the higher it is, because the rotational velocity is not changing but the distance of the object with respect to the center is. If v=w*d, then the lower the d (distance) the lower the tangential velocity.

2. Take a look at the picture:

We have the basic equation for the gravitational force.

We have to forces: Fg1, which is the original force, and Fg2, the force when the mass and the distance changes.

If we consider that mass 2 didn't change (m2'=m2), mass 1 is four times its original (m1'=4*m1) and distance is 5 times the original (r'=5*r), then next step is just plugging it into the equation for Fg2.

Dividing the original force Fg1 by the new force Fg2 (notice you can just as well do the inverse, Fg2 divided by Fg1) gives us the relation between the forces, cancelling all the variables and being left only with a simple fraction!

6 0
3 years ago
A 5.0 kg bucket of water is raised from a well by a rope. If the upward acceleration of the bucket is 3.0 m/s^2, find the force
Harman [31]
We know that m = 5 kg 
                      a  =  3.0 m/s^2
                      g = 9.8 (since not written, lets assume it's an international standard) 

T - mg =  ma

T = mg + ma

T = (5 . 9.8)  +  (5 . 3 )   

T = 49 + 15
  
T  = 64 N

Hope this helps

3 0
3 years ago
Read 2 more answers
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