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4 years ago

Which of the following might be measured in

Physics

2 answers:

gulaghasi [49]4 years ago

4 0

Answer:

The correct answer to this question is D. The area of a desk top.

Explanation:

Square meters, or m^2, are the units that represent area, or the product of two lengths. This is because the length and the width both have the units meters, so when multiplied to calculate area, the resulting units are square meters or m2. Thus, the answer for this question is D.

The length of a pendulum string would be measured in meters.

The volume of an atom would be measured in m^3 (volume is the product of the length, width, and height, giving it a cubic power). However, the volume would probably be measured in a much smaller unit because atoms are very small.

The mass of a book would likely be measured in grams or kilograms.

Gnesinka [82]4 years ago

3 0

A. The length of a pendulum string . . . No. Square meters is not a unit of length. That would be multiples or fractions of a meter.

B. The volume of an atom . . . No. Square meters is not a unit of volume. That would be multiples or fractions of a cubic meter.

C. The mass of a book . . . No. Square meters is not a unit of mass. That would be multiples or fractions of a kilogram.

<em>D. The area of a desk top</em> . . . <em>YES !</em> Square meters is a unit of area.

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3 years ago

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4 years ago

Read 2 more answers

An ideal gas, initially at a pressure of 11.2 atm and a temperature of 299 K, is allowed to expand adiabatically until its volum

Tju [1.3M]

Answer:

The pressure is $P_2 = 4.25 \ a.t.m$

Explanation:

From the question we are told that

The initial pressure is $P_1 = 11.2\ a.t.m$

The temperature is $T_1 = 299 \ K$

Let the first volume be $V_1$ Then the final volume will be $2 V_1$

Generally for a diatomic gas

$P_1 V_1 ^r = P_2 V_2 ^r$

Here r is the radius of the molecules which is mathematically represented as

$r = \frac{C_p}{C_v}$

Where $C_p \ and\ C_v$ are the molar specific heat of a gas at constant pressure and the molar specific heat of a gas at constant volume with values

$C_p=7 \ and\ C_v=5$

=> $r = \frac{7}{5}$

=> $11.2*( V_1 ^{\frac{7}{5} } ) = P_2 * (2 V_1 ^{\frac{7}{5} } )$

=> $P_2 = [\frac{1}{2} ]^{\frac{7}{5} } * 11.2$

=> $P_2 = 4.25 \ a.t.m$

8 0

3 years ago

A car (mass 5 1100 kg) is traveling at 32 m/s when it collides headon with a sport utility vehicle (mass 5 2500 kg) traveling in

Elan Coil [88]

Answer:

speed was the sport utility vehicle traveling is 14.08 m/s

Explanation:

Given data

car mass m1 = 1100 kg

speed s = 32 m/s

vehicle mass m2 = 2500 kg

to find out

speed was the sport utility vehicle traveling

solution

we will apply here conservation of momentum law

the momentum change of car is equal and opposite of the momentum change of vehicle

so equation are

m1 v1 - m2 v2 = 0

so here v2 will be

v2 = (m1 / m2 ) v1

put here all these value we get

v2 = (1100 / 2500 ) 32

v2 = 14.08 m/s

so speed was the sport utility vehicle traveling is 14.08 m/s

8 0

3 years ago