To solve this problem we will use the kinematic equations of angular motion, starting from the definition of angular velocity in terms of frequency, to verify the angular displacement and its respective derivative, let's start:
![\omega = 2\pi f](https://tex.z-dn.net/?f=%5Comega%20%3D%202%5Cpi%20f)
![\omega = 2\pi (2.5)](https://tex.z-dn.net/?f=%5Comega%20%3D%202%5Cpi%20%282.5%29)
![\omega = 5\pi rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D%205%5Cpi%20rad%2Fs)
The angular displacement is given as the form:
In the equlibrium we have to
and in the given position we have to
![\theta(t) = \theta_0 cos(5\pi t)](https://tex.z-dn.net/?f=%5Ctheta%28t%29%20%3D%20%5Ctheta_0%20cos%285%5Cpi%20t%29)
Derived the expression we will have the equivalent to angular velocity
![\frac{d\theta}{dt} = 2.7rad/s](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5Ctheta%7D%7Bdt%7D%20%3D%202.7rad%2Fs)
Replacing,
![\theta_0(sin(5\pi t))5\pi = 2.7](https://tex.z-dn.net/?f=%5Ctheta_0%28sin%285%5Cpi%20t%29%295%5Cpi%20%3D%202.7)
Finally
![\theta_0 = \frac{2.7}{5\pi}rad = 9.848\°](https://tex.z-dn.net/?f=%5Ctheta_0%20%3D%20%5Cfrac%7B2.7%7D%7B5%5Cpi%7Drad%20%3D%209.848%5C%C2%B0)
Therefore the maximum angular displacement is 9.848°
Answer:
northen henisphere,southern hemisphere, Eastern hemisphere, Western hemisphere.
Answer:
No!
Explanation:
The correct answer is x = 9.
![1s = 1.0 \times {10}^{ - 24} s \: \: = 1ys](https://tex.z-dn.net/?f=1s%20%3D%201.0%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%2024%7D%20s%20%5C%3A%20%20%5C%3A%20%3D%201ys)
1 ys is the smallest unit of time.