Can someone please help thanks
2 answers:
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Answer:
∠ CDA = 32.3°
Step-by-step explanation:
See the given figure attached to this answer.
Draw perpendiculars from B and C on AD which is BE and CF.
Now, Δ ABE is a right triangle and AE² = AB² - BE² = 7.5² - 6² = 20.25
⇒ AE = 4.5 cm
Now, DF = AD - EF - AE = 24 - 10 - 4.5 = 9.5 cm {Since BC = EF}
And CF = BE = 6 cm.
Now, Δ CFD is a right triangle and
{Where β = ∠ CDA}
⇒ Degree.
So, ∠ CDA = 32.3° {Correct to one decimal place} (Answer)
The ratio of the sides will be constant. Then the value of the length of line segment SA will be 3 ft.
The missing diagram is given below.
<h3>What is the triangle?</h3>A triangle is a three-sided polygon with three angles. The angles of the triangle add up to 180 degrees.
The triangles ΔABC and ΔSBT are the similar triangles.
Then the ratio of the sides will be constant.
BS / SA = BT / TC
10 / SA = 9 / 2.7
SA = 3
Then the value of the length of line segment SA will be 3 ft.
More about the triangle link is given below.
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