Odd integers are represented by 2n+1 where n is a whole number
consecutive odd are 2 apart so
they are 2n+1 and 2n+1+2
the sum of them is at least 16
2n+1+2n+1+2<u>></u>16
4n+4<u>></u>16
minus 4
4n<u>></u>12
divide 4
n<u>></u>3
sub back
2n+1 and 2n+3
2(3)+1 and 2(3)+3
6+1 and 6+3
7 and 9
they have to be at least 7 and 9
The line will start in the second quadrant and end in the fourth quadrant.
Answer:
−7
Step-by-step explanation:
The diagonal is solved by a^2+b^2=c^2
c=8 in this problem, so c^2=64
Since the figure is a square, a must equal b.
64/2=32, each side is root of 32 units
the square root of 32 is approximately 5.66.
Answer:
6 or 4?
Step-by-step explanation:
