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Nostrana [21]
3 years ago
6

The table below gives the list price and the number of bids received for five randomly selected items sold through online auctio

ns. Using this data, consider the equation of the regression line, yˆ=b0+b1x for predicting the number of bids an item will receive based on the list price. Keep in mind, the correlation coefficient may or may not be statistically significant for the data given. Remember, in practice, it would not be appropriate to use the regression line to make a prediction if the correlation coefficient is not statistically significant.
col1 Price in Dollars 23 24 32 37 49
col2 Number of Bids 1 2 6 9 10
Step 2 of 6: Find the estimated y-intercept =-0.488

Step 3 of 6: Determine the value of the dependent variable yˆ at x=0 is = -0.488

Step 4 of 6: Determine if the statement "Not all points predicted by the linear model fall on the same line" is False

Step 5 of 6: Substitute the values you found in steps 1 and 2 into the equation for the regression line to find the estimated linear model. According to this model, if the value of the independent variable is increased by one unit, then find the change in the dependent variable =0.290

Step 6 of 6: Find the value of the coefficient of determination =0.928

Mathematics
1 answer:
lutik1710 [3]3 years ago
6 0

Answer:

Step-by-step explanation: see attachment below

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There is only one answer to this equation. h=3/4
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3 years ago
The sum of 3 consecutive odd integers is 45 what are the three integers
Mariana [72]

Answer:

14, 15, 16

Step-by-step explanation:

45-2 <em>The difference in integers, that way they're all the same number</em>

43/3=14

14, 15, 16

6 0
3 years ago
A construction company purchased some equipment costing $300,000. The value of the equipment depreciates
goldfiish [28.3K]

Answer:

11.9\ years  

Step-by-step explanation:

we know that

The  formula to calculate the depreciated value  is equal to  

V=P(1-r)^{x}  

where  

V is the depreciated value  

P is the original value  

r is the rate of depreciation  in decimal  

x  is Number of Time Periods  

in this problem we have  

P=\$300,000\\r=14\%=14/100=0.14\\V=\$50,000

substitute the values and solve for x

50,000=300,000(1-0.14)^{x}  

(50,000/300,000)=(0.86)^{x}  

(5/30)=(0.86)^{x}  

Apply log both sides

log(5/30)=(x)log(0.86)  

x=log(5/30)/log(0.86)  

x=11.9\ years  

4 0
3 years ago
Read 2 more answers
Why is the answer to this integral's denominator have 1+pi^2
ss7ja [257]

It comes from integrating by parts twice. Let

I = \displaystyle \int e^n \sin(\pi n) \, dn

Recall the IBP formula,

\displaystyle \int u \, dv = uv - \int v \, du

Let

u = \sin(\pi n) \implies du = \pi \cos(\pi n) \, dn

dv = e^n \, dn \implies v = e^n

Then

\displaystyle I = e^n \sin(\pi n) - \pi \int e^n \cos(\pi n) \, dn

Apply IBP once more, with

u = \cos(\pi n) \implies du = -\pi \sin(\pi n) \, dn

dv = e^n \, dn \implies v = e^n

Notice that the ∫ v du term contains the original integral, so that

\displaystyle I = e^n \sin(\pi n) - \pi \left(e^n \cos(\pi n) + \pi \int e^n \sin(\pi n) \, dn\right)

\displaystyle I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n - \pi^2 I

\displaystyle (1 + \pi^2) I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n

\implies \displaystyle I = \frac{\left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n}{1+\pi^2} + C

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2 years ago
Please help with this problem
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Answer:

0.004, 4%, 1/4, 4/9.

Explanation:

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