Answer:
1.3559644*10^-^5
Step-by-step explanation:
From the information given we extract the following data
Total Number of Trials (N) = 191
Required Value (x) = 181 (notice it is not 180 since at that value we have enough passengers)
Odds of success (p) = 0.85
Using the binomial formula for calculating probability, i.e.
Inputting the values
There are many like
1(10)+10-1=19
18+1=19
30-11=19
15+4=19
Hope this help!!
The function "choose k from n", nCk, is defined as
nCk = n!/(k!*(n-k)!) . . . . . where "!" indicates the factorial
a) No position sensitivity.
The number of possibilities is the number of ways you can choose 5 players from a roster of 12.
12C5 = 12*11*10*9*8/(5*4*3*2*1) = 792
You can put 792 different teams on the floor.
b) 1 of 2 centers, 2 of 5 guards, 2 of 5 forwards.
The number of possibilities is the product of the number of ways, for each position, you can choose the required number of players from those capable of playing the position.
(2C1)*(5C2)*(5C2) = 2*10*10 = 200
You can put 200 different teams on the floor.
Answer:
Fraction 1/6. Decimal .6 or 1.6
Step-by-step explanation:
Answer:
triangle ABC was translated up 4units and left 4 units
Step-by-step explanation:
