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andre [41]
3 years ago
11

Pression Evaluate the expression -0.4(3x - 2) + 2 + 4 for x=4

Mathematics
1 answer:
denis23 [38]3 years ago
4 0

Answer:

2

Step-by-step explanation:

In this question, we will have to solve the expression with our given variable.

Plug in 4 to x and solve:

-0.4(3(4) - 2) + 2 + 4

-0.4(12 - 2) + 2 + 4

-0.4(10) + 2 + 4

Evaluate -0.4(10):

-4 + 2 + 4

-2 + 4

2

Your final answer would be 2.

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What is 336 divided by 7
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For y= 6x +(-2) what is y when x= -1
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3 0
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Suppose f⃗ (x,y,z)=⟨x,y,4z⟩f→(x,y,z)=⟨x,y,4z⟩. let w be the solid bounded by the paraboloid z=x2+y 2 z=x2+y2 and the plane z=9.z
Aleonysh [2.5K]
\mathbf F(x,y,z)=\langle x,y,4z\rangle

By the divergence theorem, the surface integral taken over S,

\displaystyle\iint_S\mathbf F\,\mathrm dS

is equivalent to the triple integral of the divergence of \mathbf F over W, the space bounded S,

\displaystyle\iiint_W(\nabla\cdot\mathbf F)\,\mathrm dV

We have

\nabla\cdot\mathbf F=\dfrac{\partial x}{\partial x}+\dfrac{\partial y}{\partial y}+\dfrac{\partial(4z)}{\partial z}=1+1+4=6

The latter integral is then given by

\displaystyle6\iiint_W\mathrm dV=6\int_{|x|\le3}\int_{|y|\le3}\int_{x^2+y^2\le z\le9}\mathrm dz\,\mathrm dy\,\mathrm dx=648
5 0
3 years ago
Integrate the following w.r.t x 1) 2x^2/3. <br>2) (5-x)^23<br>​
Kryger [21]

Answer:

A) \int\frac{2x^2}{3}dx=\frac{2x^3}{9}+C

B) \int(5-x)^{23}dx=-\frac{(5-x)^{24}}{24}+C

Step-by-step explanation:

A)

So we have the integral:

\int\frac{2x^2}{3}dx

First, remove the constant multiple:

=\frac{2}{3}\int x^2\dx

Use the power rule, where:

\int x^ndx=\frac{x^{n+1}}{x+1}

Therefore:

\frac{2}{3}\int x^2\dx\\=\frac{2}{3}(\frac{x^{2+1}}{2+1})

Simplify:

=\frac{2}{3}(\frac{x^{3}}{3})

And multiply:

=\frac{2x^3}{9}

And, finally, plus C:

=\frac{2x^3}{9}+C

B)

We have the integral:

\int(5-x)^{23}dx

To solve, we can use u-substitute.

Let u equal 5-x. Then:

u=5-x\\du=-1dx

So:

\int(5-x)^{23}dx\\=\int-u^{23}du

Move the negative outside:

=-\int u^{23}du

Power rule:

=-(\frac{u^{23+1}}{23+1})

Add:

=-(\frac{u^{24}}{24})

Substitute back 5-x:

=-(\frac{(5-x)^{24}}{24})

Constant of integration:

=-\frac{(5-x)^{24}}{24}+C

And we're done!

8 0
3 years ago
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