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3 years ago

Can anyone help me with this?

Mathematics

1 answer:

mart [117]3 years ago

7 0

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}y=3x+2&(1)\\y=5x&(2)\end{array}\right\\\\\text{substitute (2) to (1):}\\\\5x=3x+2\qquad\text{subtract 3x from both sides}\\2x=2\qquad\text{divide both sides by 2}\\x=1\\\\\text{Put the value of x to (2):}\\\\y=5(1)=5$

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e-lub [12.9K]

Answer:

The required probability is $\frac{19}{40}$

Step-by-step explanation:

The probability of obtaining a defective item from container 1 is $P(E_1)=\frac{3}{8}$

The probability of obtaining a good item from container 1 is $P(E_1)=\frac{5}{8}$

The probability of obtaining a defective item from container 2 is $P(E_1)=\frac{2}{5}$

The probability of obtaining a good item from container 2 is $P(E_1)=\frac{3}{5}$

The cases of the event are

1)Defective item is drawn from container 1 and good item is drawn from container 2

2)Defective item is drawn from container 2 and good item is drawn from container 1

Thus the required probability is the sum of above 2 cases

$P(Event)=\frac{3}{8}\times \frac{3}{5}+\frac{5}{8}\times \frac{2}{5}=\frac{19}{40}$

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3 years ago

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3 years ago

Read 2 more answers

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-BARSIC- [3]

<h2>✨ Question ✨</h2>

53 + (-26 )

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2 years ago

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