It’s -7
Because you subtract -2 with 7 and it equals 5x=-35 and then u divide it and it equals -7
We equate the derivative of the function to 0 to find the x-value at its minimum:
f'(x) = 4x + 28
0 = 4x + 28
x = -7
Now, we put this value into the original equation to find the minimum value:
f(-7) = -106
The function has a positive slope so it will increase. Thus, the range will be y > -106
The answer is B
So,
To find how much the gardener weeded in one minute, we multiply the fraction by one sixth.
In decimal form, it would be .11111111111111111111
Answer:
36 meters²
Step-by-step explanation:
Hassan built a fence around a square yard. It took 48 meters^2 of lumber to build the fence. The fence is 1.5 meters tall.
Let say square yard = x * x meters²
Perimeter of Square yard = 4x meters
Height of fence =1.5 meters
Area of fence = 4x * 1.5 =6x meters²
6x = 48
Divide both sides by 6
x = 8
Area of square yard = 6 × 6= 36 meters²
36 meters² is the area of the yard inside the fence
You probably mean the equations are y = 4 - x and y = 2x -1. Else with given equations, the solution is not possible. The steps of the solution are listed below:
Part A) The solution to the equation 4 - x = 2x + 1 are the points where both the equations have same value for a given value of x. This means, if a points (x,y) lies on both the lines it will be the solution of the given equations. Since that point lies on both the lines, both lines will cross that point. Crossing that point can be seen as intersection of two lines at that point.
Therefore, x-coordinates of the points where the graphs of equations y = 4 - x and y = 2x + 1 intersect are the solutions of the equation 4 - x = 2x + 1
Part B)The table is attached in the images below. As seen from the table, both lines have same value of y for x =1. So x=1 is the solution to the equation 4 - x = 2x + 1
Part C)In order to solve the equation 4 - x = 2x + 1 , we plot the individual lines y = 4 - x and y = 2x + 1 on the graph. The point of intersection of two lines will be the solution to the equation. The graph of lines is attached below.