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ryzh [129]
3 years ago
10

6 (x-3)=4 (x-4)+2 (x-1) how many solutions are possible for the equation

Mathematics
2 answers:
olga2289 [7]3 years ago
4 0
Indefinitely many solutions is the answer to this problem. All real numbers are solutions. The answer was 0=0.
Mila [183]3 years ago
3 0
6(x-3)=4 (x-4)+2(x-1) is equal to 6x-18= 4x-16+2x-1 which equal to 6x-18=6x-17 the rest you need to look at the text book on the chapter and section your class is on

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