2 years ago

6 (x-3)=4 (x-4)+2 (x-1) how many solutions are possible for the equation

Mathematics

2 answers:

olga2289 [7]2 years ago

4 0

Indefinitely many solutions is the answer to this problem. All real numbers are solutions. The answer was 0=0.

Mila [183]2 years ago

3 0

6(x-3)=4 (x-4)+2(x-1) is equal to 6x-18= 4x-16+2x-1 which equal to 6x-18=6x-17 the rest you need to look at the text book on the chapter and section your class is on

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