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3 years ago

Evaluate the expression (6/3+4)^2÷4×7=

Mathematics

2 answers:

kkurt [141]3 years ago

6 0

(6/3+4)^2÷4×7
(6/7)^2 /4x7
36/49 /4x7
9/7

Anastaziya [24]3 years ago

4 0

$answer = 64$

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Answer:

Step-by-step explanation:

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4 years ago

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Dvinal [7]

Answer 4

Step-by-step explanation:

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1 year ago

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What is the area of the largest rectangle with lower base on the x-axis and upper vertices on the curve y = 27 − x^2? show your

LUCKY_DIMON [66]

Answer:

Option B.

Step-by-step explanation:

The given curve is

$y=27-x^2$

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Let the vertex in quadrant I be (x,y), then the vertex in quadrant II is (-x,y) .

Length of the rectangle = 2x

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$A=54x-2x^3$ .... (1)

Differentiate with respect to x.

$\frac{dA}{dx}=54-6x^2$

Equate $\frac{dA}{dx}=0$ , to find the critical points.

$0=54-6x^2$

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Divide both sides by 6.

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The value of x can not be negative because side length can not be negative.

Substitute x=3 in equation (1).

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4 years ago

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