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4 years ago

the gold bar and the gold nuggets both contain pure gold. how many types of atoms do these objects contain?

Physics

2 answers:

Slav-nsk [51]4 years ago

3 0

Answer:

it a 11 types

if atom that in gold

Explanation:

murzikaleks [220]4 years ago

3 0

It has 11 types of dold bar

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When a wire is made smaller, the resistance increases. Which happens to the electric current?

Lelu [443]

When a wire is made shorter, the resistance decreases.

When a wire is made thinner, the resistance increases.

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4 years ago

Find the shear stress and the thickness of the boundary layer (a) at the center and (b) at the trailing edge of a smooth flat pl

melomori [17]

Answer:

a) The shear stress is 0.012

b) The shear stress is 0.0082

c) The total friction drag is 0.329 lbf

Explanation:

Given by the problem:

Length y plate = 2 ft

Width y plate = 10 ft

p = density = 1.938 slug/ft³

v = kinematic viscosity = 1.217x10⁻⁵ft²/s

Absolute viscosity = 2.359x10⁻⁵lbfs/ft²

a) The Reynold number is equal to:

$Re=\frac{1*3}{1.217x10^{-5} } =246507, laminar$

The boundary layer thickness is equal to:

$\delta=\frac{4.91*1}{Re^{0.5} } =\frac{4.91*1}{246507^{0.5} } =0.0098$ ft

The shear stress is equal to:

$\tau=0.332(\frac{2.359x10^{-5}*3 }{1} )(246507)^{0.5} =0.012$

b) If the railing edge is 2 ft, the Reynold number is:

$Re=\frac{2*3}{1.215x10^{-5} } =493015.6,laminar$

The boundary layer is equal to:

$\delta=\frac{4.91*2}{493015.6^{0.5} } =0.000019ft$

The sear stress is equal to:

$\tau=0.332(\frac{2.359x10^{-5}*3 }{2} )(493015.6^{0.5} )=0.0082$

c) The drag coefficient is equal to:

$C=\frac{1.328}{\sqrt{Re} } =\frac{1.328}{\sqrt{493015.6} } ==0.0019$

The friction drag is equal to:

$F=Cp\frac{v^{2} }{2} wL=0.0019*1.938*(\frac{3^{2} }{2} )(10*2)=0.329lbf$

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3 years ago

A bags shed and he balls stand slap DC dmss

Natalija [7]

Answer:

is that a question...?

7 0

3 years ago

An object is moving at constant speed of 5mph & the net force = 0 N. Which statement is true? a The object will stop moving.

ra1l [238]

Answer:

The object will continue moving at 5 mph ( b )

Explanation:

For an object moving at a constant speed, the forces acting on it cancels each other out, or there are no external forces atall. hence its net force = 0 N . so the true statement is that the object will continue moving at its constant speed of 5 mph because its net force = 0 N

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3 years ago

A ford escort needs a force of 3500N to accelerate at the rate of 4.9 m/s2. What is the mass of the car?

Verizon [17]

Answer:

714 kg

Explanation:

ΣF = ma

3500N = 4.9m/s^2*m

m ~= 714 kg

5 0

2 years ago