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2 years ago

A ford escort needs a force of 3500N to accelerate at the rate of 4.9 m/s2. What is the mass of the car?

Physics

1 answer:

Verizon [17]2 years ago

5 0

Answer:

714 kg

Explanation:

ΣF = ma

3500N = 4.9m/s^2*m

m ~= 714 kg

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In the process of changing a flat tire, a motorist uses a hydraulic jack. She begins by applying a force of 58 N to the input pi

AfilCa [17]

Answer:

The correct answer is "3899.92 N".

Explanation:

The given values are:

Force,

$F_{app}=58 N$

Ratio,

$\frac{R_2}{R_1}=8.2$

As we know,

Area, $A=\pi r^2$

or,

⇒ $\frac{F_2}{F_1} =\frac{A_2}{A_1}$

On substituting the value of "A", we get

⇒ $\frac{F_2}{F_1} =\frac{\pi r_2^2}{\pi r_1^2}$

⇒ $\frac{F_2}{F_1} =\frac{r_2^2}{r_1^2}$

On applying cross-multiplication, we get

⇒ $F_2=F_1\times (\frac{r_2}{r_1} )^2$

On substituting the given values, we get

⇒ $=58\times (8.2)^2$

⇒ $=58\times 67.2$

⇒ $=3899.92 \ N$

6 0

3 years ago

Image caught on Screen is called

bixtya [17]

Answer:

<h2>Virtual image</h2>

Explanation:

<h3>Virtual image can be caught on a screen</h3>

hope this helps you.

will give the brainliest!

follow ~Hi1315~

4 0

3 years ago

Read 2 more answers

The dimensions of a room are 16.40 m long, 4.5 m wide and 3.26 m high. What is the volume of the room in cubic meters? Express y

anyanavicka [17]

Answer:

the volume of the room is 240.588 meters3

The picture shows the scientific notation

3 0

3 years ago

ASAP

Yakvenalex [24]

Answer:

675 KM

Explanation:

hAVE A NICE DAY

5 0

2 years ago

Read 2 more answers

A ten-loop coil having an area of 0.23 m2 and a very large resistance is in a 0.047-T uniform magnetic field oriented so that th

inysia [295]

Answer:

The magnitude of the average emf induced in the coil is approximately o.32 V.

Explanation:

As, no. of loops = N = 10

Area = 0.23 m^2

Magnetic field = B = 0.047 T

Δt = 0.34 s

These are the given things now we have to find the EMF. So the formula of emf is:

emf = e = N×ΔФ/Δt

Therefore, ΔФ = B . ΔA = BΔAcos(θ)

Since, flux is maximum so θ = 0 and cos(0) = 1

Then,

ΔФ = BA

e = N×(BΔA)/Δt

e = 10×(0.047×0.23)/0.34

e = 0.317 V.

So, we can write it by rounding off the digit

e ≅ 0.32 V.

5 0

3 years ago