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Valentin [98]
3 years ago
9

Help please this is due in couple minutes

Mathematics
1 answer:
agasfer [191]3 years ago
5 0
63 + 64 = 127
180 - 127 = 53
m<1 = 53°
m<2 = 53°
53 + 67 = 120
180 - 120 = 60
m<3 = 60°
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Identify the variation as direct, inverse, joint or combined.
Inessa [10]
<span>a. direct variation
A relationship between two variables in which one is a constant multiple of the other. </span>
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I thought of a number, added 4 5/7 to it, and got the number 12 times as big as my original what was my number
Genrish500 [490]
Let's call the number you thought of n. Then what the two steps you took can be written as an equation:
n+4\frac{5}{7}=12n

Subtract n to get all of your variables to one side:
4\frac{5}{7}=11n

At this point, I recommend turning your mixed number into an improper fraction. It will make things easier later on:
\frac{33}{7}=11n

Now divide both sides by 11 to get the value of n:
\frac{3}{7}=n
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Slope 2 passing through 10,8
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Use y=Mx+b    with x=10 and y=8
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x^2+1/2x+1/16=4/9 Factor the perfect-square trinomial on the left side of the equation. (x + )² = 4/9
Nezavi [6.7K]
The missing number is the square-root of the constant term on the left-hand-side, which equals sqrt(1/16)=1/sqrt(16)=1/4.
Check:
(x+1/4)^2=x^2+2*(1/4)x+(1/4)^2=x^2+x/2+1/16.   ok

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An environmental group conducted a study to determine whether crows in a certain region were ingesting food containing unhealthy
nydimaria [60]

Part A

Given info:

  • xbar = sample mean = 4.90 ppm
  • s = sample standard deviation = 1.12 ppm
  • n = 23 = sample size

Because n > 30 is not true, and we don't know the population standard deviation (sigma), this means we must use a T distribution.

The degrees of freedom here are n-1 = 23-1 = 22.

At 90% confidence and the degrees of freedom mentioned, the t critical value is roughly t = 1.717

Use a T distribution table or calculator to determine this. If you don't have a calculator for the task, then you can search out "inverse T calculator" and there are tons of free options to pick from.

The margin of error E is

E = t*s/sqrt(n)

E = 1.717*1.12/sqrt(23)

E = 0.400982

This is approximate and accurate to 6 decimal places.

The confidence interval is going to be xbar plus or minus that E value

L = lower bound = xbar - E = 4.90 - 0.400982 = 4.499018 = 4.50

U = upper bound = xbar + E = 4.90 + 0.400982 = 5.300982 = 5.30

The confidence interval in the format of (L, U) is (4.50, 5.30)

You could also express it as the format L < mu < U and it would be 4.50 < mu < 5.30; however, I'll stick to the first method.

<h3>Answer:  (4.50, 5.30)</h3>

=====================================================

Part B

Since we know sigma = 2.6 is the population standard deviation, we can use a Z distribution now.

At 90% confidence, the z critical value is roughly 1.645; use a table or calculator to determine this.

n = \left(\frac{z*\sigma}{E}\right)^2\\\\n \approx \left(\frac{1.645*2.6}{0.03}\right)^2\\\\n \approx 20325.254444 \\\\

Round this up to the nearest integer to get 20326. For min sample size problems, <u>always</u> round up.

<h3>Answer: 20326</h3>
6 0
2 years ago
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