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Softa [21]
3 years ago
14

There are 60 girls and 45 boys who want to participate in a co-ed basketball tournament. if each team must have the same number

of girls and boys, what is the greatest number of team that csn enter? how many girls and.boys would be on each of those teams?
Answer 1 the greatest of team that can enter are—— teams
Answer 2, there would be—- girls and —-boys on each team.
Mathematics
1 answer:
ololo11 [35]3 years ago
5 0

Answer:

15 teams, 4 girls and 3 boys on each team.

Step-by-step explanation:

What's the greatest common multiple of 60 and 45?  It's 15.

This is the greatest number of teams that can be formed.

60/15 = 4; thus, there will be 4 girls on each team.

45/15 = 3; thus, 3 boys on each team

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The perimeter of a rectangle is 510 cm. The ratio of the length to the width is 3:2. What are the dimensions of this rectangle?
Verizon [17]
The formula to find the perimeter of a rectangle is
p  = 2(l + w)
When we put in our givens to this formula:
510 = 2 \times (3x  + 2x)
Combine x values:
510 = 2 \times 5x
Simplify right side:
510 = 10x
Isolate x, by dividing both sides by 10:
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To find length:
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For width:
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To solidify our answers:
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