All categories

3 years ago

Identify the linear graph.

Mathematics

2 answers:

jenyasd209 [6]3 years ago

5 0

The answer is: The second one. Why?

Because, when it's a linear graph, the slope of the graph cannot change.

And that's the only graph that fits the criteria

Hope this helped! c:

Mariulka [41]3 years ago

3 0

Hey, I believe the linear graph is the second one with the straight line.

You might be interested in

Which series of transformations will not map figure H onto itself

7nadin3 [17]

Answer:

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation $(x+0,y-2)$ will map vertices of the square into points

$(2,1)\rightarrow (2,-1);$
$(1,2)\rightarrow (1,0);$
$(2,3)\rightarrow (2,1);$
$(3,2)\rightarrow (3,0).$

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

$(2,-1)\rightarrow (2,3);$
$(1,0)\rightarrow (1,2);$
$(2,1)\rightarrow (2,1);$
$(3,0)\rightarrow (3,2)$

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation $(x+2,y-0)$ will map vertices of the square into points

$(2,1)\rightarrow (4,1);$
$(1,2)\rightarrow (3,2);$
$(2,3)\rightarrow (4,3);$
$(3,2)\rightarrow (5,2).$

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

$(4,1)\rightarrow (2,1);$
$(3,2)\rightarrow (3,2);$
$(4,3)\rightarrow (2,3);$
$(5,2)\rightarrow (1,2)$

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation $(x+3,y+3)$ will map vertices of the square into points

$(2,1)\rightarrow (5,4);$
$(1,2)\rightarrow (4,5);$
$(2,3)\rightarrow (5,6);$
$(3,2)\rightarrow (6,5).$

2nd transformation = reflection over y = -x + 7 will map vertices into points

$(5,4)\rightarrow (3,2);$
$(4,5)\rightarrow (2,3);$
$(5,6)\rightarrow (1,2);$
$(6,5)\rightarrow (2,1)$

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation $(x-3,y-3)$ will map vertices of the square into points

$(2,1)\rightarrow (-1,-2);$
$(1,2)\rightarrow (-2,-1);$
$(2,3)\rightarrow (-1,0);$
$(3,2)\rightarrow (0,-1).$

2nd transformation = reflection over y = -x + 2 will map vertices into points

$(-1,-2)\rightarrow (4,3);$
$(-2,-1)\rightarrow (3,4);$
$(-1,0)\rightarrow (2,3);$
$(0,-1)\rightarrow (3,2)$

These points are not the vertices of the initial square.

5 0

3 years ago

Which of the following is a solution to the equation y=-1/4x+8 and please explain the steps.

aleksklad [387]

I think it’s d .....

3 0

3 years ago

What is this h divide 4 = 9

djverab [1.8K]

Answer: 36÷4=9

Step-by-step explanation:

6 0

3 years ago

A ball is shot straight up into the air from the ground with initial velocity of 45ft/sec. Assuming that the air resistance can

Nesterboy [21]

V2^2 = V1^2 - 2gh

=> 0 = 44^2 - 2 (32.2) h 

=> h = 44^2 / 64.4 = 30.062 ft

6 0

3 years ago

What is the value of x? 27(x+4)=−6 −35 −25 25 35

Oksanka [162]

x = -38/9 !!!

27(x+4)=−6

Step 1: Simplify both sides of the equation.

27(x+4)=−6

(27)(x)+(27)(4)=−6 (Distribute)

27x+108=−6

Step 2: Subtract 108 from both sides.

27x+108−108=−6−108

27x=−114

Step 3: Divide both sides by 27.

27x/27=−114/27

x=−389

6 0

3 years ago