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Jet001 [13]
3 years ago
11

the 41st term of the arithmetic sequence is -539 and the 54th term is -708. Find the value of the 80th term

Mathematics
1 answer:
yulyashka [42]3 years ago
7 0

Answer:

a _{n} = a _{1} + (n - 1)d \\ a _{41} =  - 534 \\ a _{54} =  - 708 \\  a _{41} =  a _{1} + (41 - 1)d = - 534  \\  a _{1} + 40d = - 534 \:  \: ...(1)\\ a _{54} =  a _{1} + (54 - 1)d =- 708 \\ a _{1} + 53d = - 708 \:  \: ...(2)

Try to solve the similtanious equation to find the first term and the common difference, then use that information to figure out the 80th term... Update me if you need further help ...

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So in matt's equation, he made a mistake in the a transision from line 2 to line 3 
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in line 3: -4(4) 
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also from lines 5 to 6 he made a mistake in order of opperations (mulit division then addition and subtract)
line 5: -10+30/5
line 6: 20/5

so he first subtracted 10 then divided, he should have divided then subtracted
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Karen used the correct (-) times (+) property and the order of operations
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Answer:

x=16\dfrac{28}{37}\\ \\y=5\dfrac{1}{3}\\ \\z=7.5

Step-by-step explanation:

The diagram shows three paralel lines which divide the large triangle into three similar triangles.

By Thales theorem,

\dfrac{5}{z}=\dfrac{y}{8}=\dfrac{2}{3}

Then

\dfrac{5}{z}=\dfrac{2}{3}\Rightarrow 2z=15,\ z=7.5\\ \\\dfrac{y}{8}=\dfrac{2}{3}\Rightarrow 3y=16,\ y=\dfrac{16}{3}=5\dfrac{1}{3}

From the similarity of triangles,

\dfrac{x}{20}=\dfrac{z+8}{z+8+3}\\ \\\dfrac{x}{20}=\dfrac{7.5+8}{7.5+8+3}\\ \\\dfrac{x}{20}=\dfrac{15.5}{18.5}\\ \\x=20\cdot \dfrac{155}{185}=20\cdot \dfrac{31}{37}=\dfrac{620}{37}=16\dfrac{28}{37}

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