Answer:
one solution with a y value of 5
Step-by-step explanation:
/| x+y-4 = 0| x-y-6 = 0
We try to solve the equation: x+y-4 = 0
x+y-4 = 0 // - x-4
y = -(x-4)
y = 4-x
We insert the solution into one of the initial equations of our system of equations
We get a system of equations:
/| x+x-6-4 = 0| y = 4-x
2*x-10 = 0 // + 10
2*x = 10 // : 2
x = 10/2
x = 5
We insert the solution into one of the initial equations of our system of equations
For y = 4-x:
y = 4-5
y = -1
We get a system of equations:
/| y = -1| x = 5
I’m pretty sure they’re collinear. I’m so sorry if I’m wrong.
<u>Q</u><u>uest</u><u>ion</u><u>:</u>
To Simplify:
118 {121÷(11×11)-(-4)-(3-7)}
<u>Solu</u><u>tion</u>:
↠118 {121÷121+4-(-4)}
↠118 {1+4+4}
↠118 {5+4}
↠118{9}
↠118×9
↠1062
▬▬▬▬▬▬▬▬▬▬▬▬
The upper Solution is done by applying BODMAS
<u>Abou</u><u>t</u><u> </u><u>BODMAS</u><u>:</u>
B→ Bracket
O→ Of
D→ Division
M→ Multiplication
A→ Addition
S→ Subtraction
Y-99=-1/33(x-22)
a). y = 1/33x + 98 1/3
b) 33y = x + 109 1/3
x - 33y = -109 1/3
Answer:
36.5cm²
Step-by-step explanation:
Area of quarter circle=8²
/4=64/4=16cm²
Area of square+Area of shaded region =2(16)=32=100.5cm²
Area of square=8²=64cm²
Area of shaded region=100.5cm²-64cm²=36.5cm²
Therefore, the area of the shaded region is 36.5cm².
